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The answer depends on how much chicken wire he has. The greatest area is enclosed if it is in the form of a circle with the quantity as the perimeter.

So, if he has L metres of chicken wire, he can make a circular shape of 2*pi*r = L

where r is the radius.

So r = L/(2*pi) metres.

Then area = pi*r2 = pi*[L/(2*pi)]2 metres = L2/(4*pi) sq metres

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Q: What is the greatest number of square meters Mr Quinn can enclose with the amount of chicken wire he has?
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