if you mean -5/3 - 4/5 the answer is -2.4 if you mean -5/3-4/5 the answer is -1.13 ((-5)/3) - (4/5) = -2.4667 (-(5/3)) - (4/5) = -2.4667
4
343
5/8 ÷ 3/4 = 5/8 × 4/3 = (5×4)/(8×3) = 20/24 = 5/6
5
The grade level of Kumon D11 typically corresponds to around 4th to 5th grade in the Kumon Math program. In Kumon, the levels are not directly tied to traditional grade levels but rather focus on individual mastery of specific skills. D11 in Kumon Math usually covers topics such as fractions, decimals, and more complex arithmetic operations. Students progress through the Kumon levels at their own pace based on their mastery of each concept.
1. Are you cheating on me? 2. Are you a virgin? 3. Do you love me? 4. Since When? 5. Why?
Hardest 1.SDSU 2.Cal Poly SLO 3.Cal State Long Beach 4.SFSU 5.San Bernardino
They will be in Grade 3 . Grade 1 : 6 Grade 2 : 7 Grade 3 : 8 Grade 4 : 9 Grade 5 : 10 Grade 6 : 11 Grade 7 : 12 Grade 8 : 13 Grade 9 : 14 Grade 10 : 15 and so on.
You got 75% correct.Reason:5 is 1/4 of 20, therefore meaning that you got 3/4 correct. And of course 3/4 = .75, or 75%
No. It isn't.
The Primate Order is a Mammalian order consisting of 5 grades split into prosimians (grade 1 and 2) and anthropoids (grade 3, 4 and 5) (each with subdivisions), grade 1 are all extinct and resemble todays treeshrews (which are not primates), grade 2 are prosimians such as lemurs, grade 3 are the tarsiers which have characteristics of both prosimians and anthropoids but DNA shows they are anthropoids. Grade 4 are the monkeys which are divided into New and Old world (and each again have subdivisions). Grade 5 are the apes (lesser and great)
1-1 1-2 1-3 1-4 1-5 1-6 2-1 2-2 2-3 2-4 2-5 2-6 3-1 3-2 3-3 3-4 3-5 3-6 4-1 4-2 4-3 4-4 4-5 4-6 5-1 5-2 5-3 5-4 5-4 5-6 6-1 6-2 6-3 6-4 6-5 6-6 So there ARE 36 possible outcomes, you see. Answer BY: Magda Krysnki (grade sevener) :P
1. yes 2. 3.14 3. 5 4. 680 5. 12
It's call a 5 star General and it is the top rank in Halo 3
b-
The following example sets up a two-dimensional array, initialises it with some pseudo-random data, and then prints the table and the averages. #include<iostream> #include<time.h> int main() { const int max_students = 7; const int max_student_grades = 5; const int max_grades = 6; const char grade[max_grades]={'A','B','C','D','E','F'}; srand((unsigned) time(NULL)); // Initialise the array with pseudo-random grades: int table[max_students][max_student_grades]; for(int student=0; student<max_students; ++student) { for(int student_grade=0; student_grade<max_student_grades; ++student_grade) { table[student][student_grade] = rand()%max_grades; } } // Print the table and average the results. int overall=0; for(int student=0; student<max_students; ++student) { int average=0; std::cout<<"Student #"<<student+1; for(int student_grade=0; student_grade<max_student_grades; ++student_grade) { std::cout<<" Grade #"<<student_grade+1<<": "<<grade[table[student][student_grade]]<<", "; average+=table[student][student_grade]; } std::cout<<" Average: "<<grade[average/max_grades]<<std::endl; overall+=average; } std::cout<<"Overall average: "<<grade[overall/max_grades/max_students]<<std::endl; return(0); } Example output: Student #1 Grade #1: A, Grade #2: E, Grade #3: D, Grade #4: E, Grade #5: F, Average: C Student #2 Grade #1: E, Grade #2: D, Grade #3: E, Grade #4: E, Grade #5: E, Average: D Student #3 Grade #1: D, Grade #2: A, Grade #3: D, Grade #4: B, Grade #5: A, Average: B Student #4 Grade #1: C, Grade #2: B, Grade #3: A, Grade #4: A, Grade #5: B, Average: A Student #5 Grade #1: E, Grade #2: D, Grade #3: C, Grade #4: F, Grade #5: E, Average: D Student #6 Grade #1: C, Grade #2: D, Grade #3: A, Grade #4: F, Grade #5: A, Average: B Student #7 Grade #1: B, Grade #2: D, Grade #3: F, Grade #4: B, Grade #5: C, Average: C Overall average: C