When a ray of light passes from material 1 to material 2:
N1 sin θ1 = N2 sin θ2
where N1 & N2 are the refractive indices of the materials, and θ1 is the angle of incidence, θ2 the angle of refraction.
From air to the material:
N1 = 1.00,
θ1 = 40°,
θ2 = 50°,
N2 = unknown, the index of refraction of the material:
→ 1.00 x sin 50° = N2 x sin 40°
→ N2 = 1.00 x sin 50° ÷ sin 40°
→ N2 ≈ 1.1917 (the index of refraction of the material)
The answer depends on the angle between the mirrors. The distance between the mirrors does not, in theory, make any difference. If the angle between the mirrors is x degrees, then the theoretical number of images is (360/x)- 1 which is rounded down. In practice, minor defects in the mirrors, refraction, total internal refraction, absorptions, scattering etc will reduce the number of images.The answer depends on the angle between the mirrors. The distance between the mirrors does not, in theory, make any difference. If the angle between the mirrors is x degrees, then the theoretical number of images is (360/x)- 1 which is rounded down. In practice, minor defects in the mirrors, refraction, total internal refraction, absorptions, scattering etc will reduce the number of images.The answer depends on the angle between the mirrors. The distance between the mirrors does not, in theory, make any difference. If the angle between the mirrors is x degrees, then the theoretical number of images is (360/x)- 1 which is rounded down. In practice, minor defects in the mirrors, refraction, total internal refraction, absorptions, scattering etc will reduce the number of images.The answer depends on the angle between the mirrors. The distance between the mirrors does not, in theory, make any difference. If the angle between the mirrors is x degrees, then the theoretical number of images is (360/x)- 1 which is rounded down. In practice, minor defects in the mirrors, refraction, total internal refraction, absorptions, scattering etc will reduce the number of images.
f a line is drawn parallel to the angle of incidence axis (X-axis), it cuts the graph at two points, showing that there are two values of angle of incidence for an angle of deviation. However, at the point of angle of minimum deviation, the line will be tangent to the curve showing that for minimum angle of deviation there is only one angle of incidence.
The supplement of an angle is the angle that, when added to the original angle, equals 180 degrees. The complement of an angle is the angle that, when added to the original angle, equals 90 degrees. Therefore, the supplement of the complement of a 38-degree angle would be the angle that, when added to the complement of 38 degrees (52 degrees), equals 180 degrees. This angle would be 128 degrees.
The reference angle for an angle with the measure of 175 degrees is 5 degrees
30 degrees
A right angle.
The answer is zero. (From Snell's law, if AI in the angle of incidence, AR is the angle of refraction, and n is the refractive index of the material doing the refracting, then: AR = arcsin[(1/n)sin(AI)] =0 if AI=0.
No, doubling the angle of incidence itself will not cause a doubling of the angle of refraction.
The angle of incidence
If the angle of incidence equals the critical angle, the angle of refraction would be 90 degrees. This occurs when light travels from a denser medium to a less dense medium and undergoes total internal reflection.
Angle of refraction will be less compared to the angle of incidence in this case.
greater than the angle of refraction
less than the angle of refraction.
The COEFFICIENT of Refraction.
The angle of incidence is the angle between the incident ray and the normal to the surface, while the angle of refraction is the angle between the refracted ray and the normal to the surface. These angles are related by Snell's Law, which states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the refractive indices of the two media the light is traveling through.
40
The angle if refraction also increases.