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Yes, it is.
Linear Average is the initial value plus the final value divided by two.
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The initial value must lie in the interval (24.5, 25.5). It is not possible to be any more precise since any one of those values is possible.
if X(Z) is a Z-transform of x[n] and X(Z) is causal then the initial value theorem states that the lim as z tends to infinity for X(Z) must eqaul x(0).