use this strategy: integral of (b^x) dx = (b^x)/ln(b) + K [K is integration constant, b is not a variable]
rewrite (1/c)^(1-x) = ((1/c)^1)*((1/c)^(-x)) = (1/c)*(c^x). (1/c) is a constant, so bring outside the integral, then let b = c in the formula above, and you have (1/c)*(c^x)/ln(c) + K
3^-1 = 1 over (3 to the power of 1) = 1/3, one third. a minus power is the same as a normal power but with a 1 above it.
the integral of the square-root of (x-1)2 = x2/2 - x + C
3 to the power of 1 is 3. 3 to the power of minus 2 is equal to 1 over 3 to the power of 2. 3 to the power of 2 is 9. 3 to the power of 1 times 3 to the power of minus 2 is the same as... 3 divided by 3 to the power of 2. So that gives us 3 divided by 9 which is the same as 1/3.
10 to the power 3 means 10*10*10, or 1000 10 to the power MINUS 3 means 1 over 10 to the power 3, so 1/1000.
3 and 2/5 minus 1 and 1/3 = 2 and 1/15
3^-1 = 1 over (3 to the power of 1) = 1/3, one third. a minus power is the same as a normal power but with a 1 above it.
the integral of the square-root of (x-1)2 = x2/2 - x + C
1 to any integral power is 1.
It depends on the maximum value of c. In signed values, the maximum value we can store in an integral is 2 to the power of the number of bits in the integral, minus 1. Thus a 32-bit signed integral can accommodate all positive values in the range 2^31, which is 2,147,483,648.
10-4= 1 1 104= 10000 the answer is 1 over 10000.
3 to the power of 1 is 3. 3 to the power of minus 2 is equal to 1 over 3 to the power of 2. 3 to the power of 2 is 9. 3 to the power of 1 times 3 to the power of minus 2 is the same as... 3 divided by 3 to the power of 2. So that gives us 3 divided by 9 which is the same as 1/3.
10 to the power 3 means 10*10*10, or 1000 10 to the power MINUS 3 means 1 over 10 to the power 3, so 1/1000.
it is 1/16777216 because you just do 16 to the power of 6 then put a one over it
integral x/(x-1) .dx = x - ln(x-1) + c where ln = natural logarithm and c = constant of integration alternatively if you meant: integral x/x - 1 .dx = c
10 to the power of minus 1 is equal to 1 divided by 10, which is 0.1. This can be calculated by taking the reciprocal of 10 raised to the power of 1, which is 10. Therefore, 10 to the power of minus 1 is equivalent to 0.1.
1
Unfortunately, 2 over 2 minus 1 equals 5 over 6 is just a wrong answer! If it is 2 over 2, minus 1, the answer is that it equals zero. If it is 2, over 2 minus 1, the answer is that it equals 2.