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What is monthly interest payment on a 10000 loan for 5 years at 12 percent interest?
The monthly interest is 100.
What is 2 percent of 600?
2% of 600 is 12
What is 12 percent of 5000?
12% of 5000= 12% * 5000= 0.12 * 5000= 600
What would be the amount of compound interest on 8000 invested for two years at 12 percent compounded semiannually?
Semiannually over two years is equivalent to 4 periods. If the interest is 12% every 6 months, then the amount of interest is It is 8000*[(1.12)4 -1] =4588.15
You invest a single amount of 10000 for 5 years at 10 percent at the end of 5 years you take the proceeds and invest them for 12 years at 15 percent How much will you have after 17 years?
Compound interest, no tax, annual interest rates? If so - Sum after the first 5 years - (1000 x (1.15)) Sum after the next 12 years - (proceeds from the 5 year investment x (1.1512))
How much money would have to be deposited now at 3 percent interest compounded monthly to accumulate to 600 in 4 years?
b * 1.03 4*12 = 600 b = 600 / 1.0348 b ≈ 600 / 7.977 b ≈ 145.20
What is the percent 2 percent percent of 600?
2% of 600 is 12.
What is monthly interest payment on a 10000 loan for 5 years at 12 percent interest?
The monthly interest is 100.
What is 2 percent of 600?
2% of 600 is 12
What is two percent of 600?
2% of 600 = 600*2/100 = 12
What percent is 12 out of 600?
ANSWER: 2%% rate:= 12/600 * 100%= 0.02 * 100%= 2%
What is 12 percent of 600 show work?
600 x 0.12 = 72
What is the interest on 950 invested for 4 years in an account that earns simple interest at a rate of 3 percent per year?
3% for 4 years is equivalent to 12% of the principal, in this case 12 x 9.5 which is 114.
How much would 500 invested at 6 percent interest compounded anually be worth after 12 years?
$500 (1.06)12 = $1,006.10
What is 12 percent of 5000?
12% of 5000= 12% * 5000= 0.12 * 5000= 600
How much would 220 invested at 10 percent interest compounded continuously be worth after 12 years?
730.43
How much would 500 invested at 6 percent interest compounded annually be worth after 12 years?
1006.1
