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inverse log of 2= 1/(log{10}2)= 1/(log2)=1/0.3010299=3.3219. hence answer is 3.3219

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If the base for logarithms is b then inverse logb 2 = b2. Since the default base for log is 10, inverse log 2 = 102 = 100.

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11y ago
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Q: What is the inverse log of 2?
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