989.
If there is a remainder of 2 when divided by 3, the number is one less than a multiple of 3.
If there is a remainder of 4 when divided by 5, the number is one less than a multiple of 5.
Thus the number required is one less than a multiple of the lowest common multiple of 3 and 5 (that is 15).
So what is needed is an even multiple of 15 less than or equal to 1000:
1000 ÷ 15 = 662/3
Thus the highest even multiple of 15 not greater than 1000 is 66 x 15 = 990, and the required number is 989.
799
A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.
5
26
14. The largest possible number for a remainder is 1 less than the divisor.
799
It is 997.
The largest 2-digit number is 99. When 99 is divided by 4, the quotient is 24 with a remainder of 3. This is because 99 divided by 4 equals 24 with a remainder of 3.
A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.
3
5
It is an integer which, when divided by 2, leaves a remainder of 1.
It is a factor of that number and leaves no remainder
209
26
11
85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11