What is the largest number of children that can share equally 72 sweets and 54 chocolates?

Answer 1

72+54=126 therefore 126 children have 1 sweet each

Answer 2

To find the largest number of children that can share equally 72 sweets and 54 chocolates, we need to find the greatest common divisor (GCD) of 72 and 54. The GCD of 72 and 54 is 18. Therefore, the largest number of children that can share equally is 18. Each child would receive 4 sweets and 3 chocolates.

Answer 3

Well, honey, let me break it down for you. The largest number of children that can share equally 72 sweets and 54 chocolates is 18. Why? Because both 72 and 54 can be divided by 4, and the greatest common factor of 72 and 54 is 18. So, gather 18 hungry kiddos and watch those treats disappear!

Answer 4

Oh, dude, that's easy! So, the largest number of children that can share equally 72 sweets and 54 chocolates is the greatest common divisor of 72 and 54, which is 18. So, 18 lucky kids can each get 4 sweets and 3 chocolates. It's like a sweet tooth party for them!

Answer 5

18

Answer 6

18

Answer 7

1