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Is the GCF of 4x2y3 and 6xy2 2xy2?
X4y6
What is the answer to x plus y to 3rd power plus x minus y to 3rd power?
(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)
How do you find the coordinates of one of the vertices for the parabola ysquared-6x plus 4y plus 16 equals 0?
The quadratic is "sideways" which has the form: x = ay2 + by + c,or the vertex form: x = a(y - k)2 + h where (h, k) is the vertex.y2- 6x + 4y + 16 = 0y2+ 4y + 16 = 6xy2+ 4y + 4 - 4 + 16 = 6x(y + 2)2 + 12 = 6x(1/6)(y + 2)2+ 2 = x(1/6)[y -(-2)]2+ 2 = xThus, the vertex is (2, -2).
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