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The width can be any number greater than zero and less than the square root of 35, and the length can be any number greater than the square root of 35, subject to the constraint that the product of the length and the width must be 35.

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Q: What is the length and width of 35 meters squared?
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If width of a rectengle is 2 inches less than its length and the area is 35 square inches what are the length and the width of the rectangle?

Let the width be (x-2) and the length be x: width*length = area (x-2)*x = 35 square inches x2-2x = 35 x2-2x-35 = 0 Solving the above quadratic equation works out as: x = -5 or x = 7 it must be the latter because dimensions can't be negative Therefore: length = 7 inches and width = 5 inches Check: 7*5 = 35 square inches


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