Best Answer

Assuming you mean a golden rectangle as opposed to one which can be split up into squares:

length = width × φ

= width × (√5 + 1)/2

= 55 × (√5 + 1)/2

≈ 89.0 units

Q: What is the length of a perfect rectangle with width W 55?

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Perimeter = 32 inches. Area = 55 square inches.

990 square feet. To calculate square feet simply multiply length by width - the result is the area in square feet.

I'm having some trouble understanding exactly what 'm' and 'x' have to dowith the rectangle. A look at the drawing would really help.the answer is 70 -FlyBoi

64

The basic unit of length in the metric system is the meter. Grams are used to measure weight and liter is used to measure liquid capacity.

Related questions

Prime factors of 55 are 5 and 11, which differ by 6, so length 11m, width 5m!

55 sq cm

this is not a square, but a rectangle, first off. second, the rectangle's area is 2475 square feet.

Perimeter = 32 inches. Area = 55 square inches.

A rectangle = LW If the diagonal of length of 10 ft makes a 55⁰ angle with length L, then the length of width W equals to 10 sin 55⁰ ft, and the length of L equals to 10 cos 55⁰ ft. So that A = LW = (10 sin 55⁰ ft)(10 cos 55⁰ ft) ≈ 47 ft2

A rectangle has two pairs of equal sides. So to calculate the perimeter, add two known sides and multiply by two. 45 + 10 = 55 55 x 2 = 110 Perimeter - 110 metres.

16 and 12

The perimeter of a rectangle is twice the width added to twice the length -> 2(W) + 2(L) We are told that for this rectangle the perimeter = 2(W) + 110 So for this rectangle 2(L) = 110 Therefore L = 55 But this does not tell us enough to work out the width ..... if the width is 1 cm then the perimeter would be 2(1) + 110 and if the width is 300 cm then the perimeter would be 2(300) + 110 In each case the perimeter meets the requirement of being 110 cm more than twice the width.

length and width for a 55 gallon fish tank

Height x Width x Length. Measure the height, width and depth of the object, and be sure to do it in the same units. Then multiply them together. H x W x L = Volume of the rectangular solid The answer should be in units cubed. As an example, a rectangle has these dimensions: Length = 55 mm Width = 30 mm Length = 40 mm 55 X 30 X 40 = 66,000 cubic millimeters (mm3)

11 and 5

There is not enough information to answer the question. First of all, the shape of the area is unknown. Even if it were a rectangle, all that can be said is that one of the sides must be at least sqrt(500) = 22.36 ft (approx). Take any number L greater than 22.36 and let W = 500/L Consider a rectangle with Length = L ft and Width = W ft. The area of such a rectangle is L*W = L*(500/L) = 55 sq ft. But L is ANY length more than 22.36 feet. There are infinitely many possible values for L.