Area = 64 cm2 so length of side = 8cm
Then, by Pythagoras, length of diagonal = sqrt[82 + 82] = 8*sqrt(2) = 11.3137 cm (to 4 dp)
We have no idea what "a 64cm square" means, since such a thing cannot exist. If you mean to say "a square with an area of 64 square cm", then its side length is 8 cm.
If the area of the square is 64 square cm then its sides are 8 cm. Its perimeter: 8+8+8+8 = 32 cm
The perimeter of any polygon is the sum of the lengths of all the sides. Specifically in the case of a square, since it has 4 sides of equal length, the perimeter is simply 4 times the length of any side.
Convert to the same units then you can compare the numbers. 1 cm = 10 cm → 64 cm = 64 × 10 mm = 640 mm 640 > 630 → 640 mm > 630 mm → 64 cm > 630 mm → 64 cm is greater than 630 mm.
It is: 64/4 = 16 cm
8 x 8 = 64cm squared
The radius will turn out to be the square root of the area divided by pi which in this case is about 4.51351666838205 cm
We have no idea what "a 64cm square" means, since such a thing cannot exist. If you mean to say "a square with an area of 64 square cm", then its side length is 8 cm.
50-64cm
Perimeter of a square is given by 4a where 'a' is the side of square. Just put 64 equals to 4a which gives a=16
a square has 4 equal side so one side = 32/4 = 8 8 squared = 64cm
A side length would be 64/4 which is 16 16 times 16 is 256
Yes an area problem must have an squared unit. Suppose: Find the area of a suare with side 8 cm. Thus, 8 squared will be 64cm. Your answer will be 64 squared cm.
64cm.
It is: 4*2 = 8 square cm
If the area of the square is 64 square cm then its sides are 8 cm. Its perimeter: 8+8+8+8 = 32 cm