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Limit as x tends to ∞: x/e^x
As you can see, as x approaches infinity, the sum becomes ∞/∞. Now we use l'Hospitals rules.
d/dx(x) = 1 (Derivative)
d/dx(e^x) = e^x (Derivative)
therefore, the sum can be written as lim x tends to ∞ 1/e^x
Now as x approaches infinity, the sum = 1/∞ = 0
Therefore, lim x tends to infinity: x/e^x = 0
What else can I help you with?
What is e to the power infinity?
E to the power infinity, or lim en as n approaches infinity is infinity.
What is e to the power minus infinity?
that would be the inverse of e to the plus infinity Answer is thus zero
What is e to the negative 2 times infinity?
I can see two different ways to place the parentheses in that question. Here are both answers: ( e-2 ) x infinity = infinity ( e-2 x infinity ) = zero
What is higher than infinity?
Trans infinity
What is e to the power imaginary infinity?
???
What is the limit of x as it approaches infinity for e to the negative 2x divided by the square root of 1-x squared?
1
What is the answer to limit as x approaches infinity of e raised-x squared?
limit x tends to infinitive ((e^x)-1)/(x)
What is e to the power infinity?
E to the power infinity, or lim en as n approaches infinity is infinity.
What is e equivalent to?
e is defined as the limit of (1 + 1/x)^x as x approaches infinity. It is an irrational number. The decimal approximation is 2.71828183
What is the meaning of e in math?
The number e is an important mathematical constant that is the base of the natural logarithm. It is approximately equal to 2.71828, and is the limit of (1 + 1/n)n as n approaches infinity, an expression that arises in the study of compound interest.
What is the limit of x divided by e to the x as x approaches negativ infinity?
lim x -> -inf [x/ex] = lim x -> +inf[-x/e-x] = - lim x -> +inf [ xex ] = -infIf you want to see this function then I suggest you use either:(a) wolframalpha.com: put in show me x/exp(x)or (b) geogebra, which is available for the desktop.
What is e to the power plus infinity?
infinity
What is e raise power to infinity?
Infinity
Given y plus 6y' plus 13 y equals 0. How do you find the frequency of the oscillation and describe the motion as t to infinity?
well, simplifying: 6y'+14y=0 Take y=c*e^(rt), substitute and divide by c*e^(rt): 6r+14=0, r=-7/3 y=c*e^(-7t/3), no oscillation occurs. However, if you meant y''+6y'+13y=0, Use the same methods: r^2+6r+13=0 Solving, r=-3 plus or minus 2i substituting r and using superposition principle. y=(e^(-3t))(c_1cos(4t)+c_2sin(4t)) Frequency is probably period which is 2pi/4=pi/2, and taking the limit as t approaches infinity e^(-3t) is zero so the sine and cosine terms don't matter. So y approaches zero as t approaches infinity.
Is it generally true that limit of e to the power of fx as x tends to infinity is equal to e to the power of limit of fx as x tends to infinity?
In general, for a continuous function (one that doesn't make sudden jump - the type of functions you normally deal with), the limit of a function (as x tends to some value) is the same as the function of the limit (as x tends to the same value).e to the power x is continuous. However, you really can't know much about "limit of f(x) as x tends to infinity"; the situation may vary quite a lot, depending on the function. For example, such a limit might not exist in the general case. Two simple examples where this limit does not exist are x squared, and sine of x. If the limit exists, I would expect the two expressions, in the question, to be equal.
What is e to the power minus infinity?
that would be the inverse of e to the plus infinity Answer is thus zero
What is e to the negative 2 times infinity?
I can see two different ways to place the parentheses in that question. Here are both answers: ( e-2 ) x infinity = infinity ( e-2 x infinity ) = zero
