Join the centre of the circle O and the point A .Extend it to both sides to form a line.This is the required locus
Use the four-step process to find the slope of the tangent line to the graph of the given function at any point.
By using the other information supplied about the circle to calculate either its radius (from which its area can be calculated) or its area (if the circle is similar to another with a given area and some ratio between the two circle is given):If the diameter is given: radius = diameter ÷ 2If the circumference is given: radius = circumference ÷ 2πIf the circle is similar to another circle which has a given area, and the length ratio is given; square the length ratio to get the area ratio and apply to the given area.
let the two circles with centre O and P are congruent circles, therefore their radius will be equal. given: AB and CD are the chords of the circles with centres O and P respectively. ∠AOB=∠CPD TPT: AB=CD proof: in the ΔAOB and ΔCPD AO=CP=r and OB=PD=r ∠AOB=∠CPD therefore by SAS congruency, ΔAOB and ΔCPD are congruent triangle. therefore AB=CD
That's a circle.It is a circleThat's a circle.
If you are given the radius of the circle, you can use the formula: diameter = 2*radius If you are given the circumference of the circle, you can use the formula: diameter = circumference/pi
... touches each circle in exactly one point on each circle. given any two circles where none is entirely inside or inside and tangent to the other, there are at most four straight lines that are tangent to both circles.
A tangent is a straight line that touches the circumference of a circle at a given point
the circle is inscribed in the polygon :]
The direction of a particle moving in a circle at a given time can be found by determining the tangent to the circle at that point. The tangent is perpendicular to the radius of the circle at that point and indicates the direction of motion.
Not enough information has been given to find the tangent BC but it will be perpendicular or at right angles to the radius of the circle.
Letting x be radius of the 4 circles, then (squareroot(2x^2))+x=10, or x(1+sqrt2)=10. Then radius of circle in middle is ((2*10)-4x)/2. So I get radius of circle in middle = 1.715729 approximately.
If you're only given two points, and you're told that they both lie on a circle,then there are an infinite number of possible circles, and therefore an infinitenumber of possible centers. In order to pin it down, you need three points.
The tangent line only touches the outside of a circle at one given point. So an outside line perpendicular to the circle's diameter at 90 degrees should do.
Infinite lines because a circle has infinite lines of symmetry.
A circle's tangent is exactly the same as a triangle's tangent. If you look at a circle, you can make the radius the hypotenuse. Then make a vertical line from the point, and a horizontal line from the center. If you look, you have a triangle made inside the circle. This is why angles can be measured in radians, a unit that is derived from the circumference of a circle.-------------------------------------------------------------------------------------------By doing a little calculus, we find that the slope of the equation of a circle-the slope of the tangent line-is given by the tangent of an angle.AnswerEverything written above is correct, but doesn't have anything to do with tangents (in the circle sense of the word). Suppose you're given an angle theta. Draw a circle together with two radii, one horizontal and the other at an angle theta from the first one. (So far, this is the same as above.) Now draw the tangent to the circle at X, the point where the non-horizontal radius meets the circumference. Let Y be the point where this tangent meets the horizontal line through the centre. Then, assuming the radius is 1, tan(theta) is the distance XY, which is the length of part of the tangent.
Yes, that is correct. Circles circumscribed about a given triangle will have centers that are equal to the incenter, which is the point where the angle bisectors of the triangle intersect. However, the radii of these circles can vary depending on the triangle's size and shape.
False