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Wiki User
∙ 14y ago8, 9, 11 and 12
First, to find median put numbers in order so: 5, 5, 6, 7, 8, 9, 10, ( 10, 12 ,) 14, 15, 17, 18, 18, 18, 20 10 + 12= 22 divided by 2= 11, the median is 11
median = 11.5 mean = 12
11
As there are 6 numbers, the median is half way between the middle numbers, or (7+9) / 2 = 8
8, 9, 11 and 12
Mean: 20.2222222 Median: 12 Mode: 11 Range: 79
The middle two numbers are 8 and 10 so the median is 9.
First, to find median put numbers in order so: 5, 5, 6, 7, 8, 9, 10, ( 10, 12 ,) 14, 15, 17, 18, 18, 18, 20 10 + 12= 22 divided by 2= 11, the median is 11
One possible set is {9, 9, 10, 11, 12, 15, 18}
These are your 5 numbers: X X X X X the median (the middle number of a row) is 11, that means: X X 11 X X the mode (the most frequent number in a row) is 12, that means: X X 11 12 12 the mean (the average) is 10, that means: (X+X+11+12+12)/5=10 or: X+X+11+12+12=50 or: X+X=50-12-12-11 or: X+X=15 so the remaining numbers must be 15 combined, and lower then 11, that means they can be: 5 and 10 6 and 9 7 and 8 so you have 3 possible solutions: 5 10 11 12 12 6 9 11 12 12 7 8 11 12 12
List the numbers in order. If there is an ODD number of numbers, the median is the number in the middle (eg if there are 11 numbers listed, the median is the (11+1)÷2 = 6th number). If there is an EVEN number of numbers, the median is the mean of the middle two (eg if there are 12 numbers listed, the median is the mean of the (12÷2) = 6th and the 6th+1 = 7th numbers, ie (6th+7th)÷2.)
Yes. In the set (9, 10, 11, 12, 13) 11 is the median and the mean.
10 numbers in the sample. Middle numbers are 10 and 14. Then the median is (10+14)/2=12
1 5 6 8 10 11 12 13 The median (or middle number) is 9.
The median of the numbers 10 12 13 17 17 18 27 is 17.
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