A set of twelve numbers, with a mean value of 45/6, a median of 3, and a mode of 3.
The first 8 prime numbers are: 2 3 5 7 11 13 17 and 19 The median is: (7+11)/2 = 9
The median is simply the number in the middle when ordered from least to greatest. Since there is an even number of terms here, simply find the average of the middle two. In this case, the average of 8 and 11 is 9.5 Therefore, the median is 9.5
The median of 5, 7, 11, 14, 8, 7, 11, 3, 0, and 7 is 7.
13
The are 11, 17 and 24.
A set of twelve numbers, with a mean value of 45/6, a median of 3, and a mode of 3.
To find the median of a step of numbers, you must first order them from least to greatest. 1) 2, 3, 7, 9, 11, 13 Now begin crossing off the highest number and the lowest number until you are left with either one or two numbers. 2) 2, 3, 7, 9, 11, 13 2) 2, 3, 7, 9, 11, 13 Now you are left with two numbers. To find the median we need to find the mean (average) of the remaining two numbers. Simply add the two numbers together and divide by 2. Your answer for this will be the median for the set of numbers. 7 + 9 = 16 ÷ 2 = 8. So the median for {2, 3, 7, 9, 11, 13} = 8.
It is 9.
9
The answer is 8.5
Mean: 7 Median: 6 Mode: 1, 9, 4, 7, 5, 3, 16, 11
The first 8 prime numbers are: 2 3 5 7 11 13 17 and 19 The median is: (7+11)/2 = 9
(-33/91) / (-3/77) =(33/91) / (3/77) = (33/91) * (77/3) = (11/91)*(77/1) =(11/13)*(11/1) = 121/13(-33/91) / (-3/77) =(33/91) / (3/77) = (33/91) * (77/3) = (11/91)*(77/1) =(11/13)*(11/1) = 121/13(-33/91) / (-3/77) =(33/91) / (3/77) = (33/91) * (77/3) = (11/91)*(77/1) =(11/13)*(11/1) = 121/13(-33/91) / (-3/77) =(33/91) / (3/77) = (33/91) * (77/3) = (11/91)*(77/1) =(11/13)*(11/1) = 121/13
15 - it has 3 numbers either side of it.
The median of 2 3 5 7 11 is 5, the central number.
six