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median is 79.
Write in order; median is middle number:
{72, 89, 67, 81, 75, 79, 81, 80, 62, 64, 83}
→ {62, 64, 67, 72, 75, 79, 80, 81, 81, 83, 89}
To find middle number, count the number of data items, add 1 and divide by 2.
If this is a whole number, that is the data item which is the median; if it is a fraction, take the mean average of the data items of the positions either side of the fraction (eg if the fraction is 3.5, take the mean average of the 3rd and 4th data items)
There are 11 data items → median is (11+1)/2 = 6th data item
→ median is 79
What else can I help you with?
What is the mean mode and median of this data 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64?
step 1. arrange the numbers in ascending order (from low to high) as follows. was: 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64 now: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 step 2. count the number of the numbers above, or assign an index as follows. string: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 index: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 so the count is 20. The mode is the number most frequently observed. The mode is 65, which occurs four times. The median is the number in the middle. In this case, the 10th and 11th numbers both qualify for consideration. We take the average of the two numbers. The median is therefore 67. Alternate methods: 1) Use Microsoft Excel statistical functions of =mode() and =median() 2) Draw a bar graph with the horizontal axis of integers from 62 to 80. The y-axis is the frequency observed for that specific x value. For example, the frequency for 62 is one. The frequency for 63 is zero, and so on. The mode is the bar with the highest count. The median is not so obvious from a bar graph, unless the distribution is symmetric. Need some manual counting.
What is the median of 61 62 64 68 70 71 72?
It is 68, the number in the middle when they are arranged in order.
What is the median of 57 57 62 64 69 69 69 72 73 73 75 78 80 81?
There are 14 numbers - therefore, the median number is halfway between the seventh and eighth number. This is therefore 70.5.
How do you calculate the varience?
find varience fo rthis numbers 71, 67, 70, 59, 71, 68, 67, 71, 80, 68, 74, 69, 72, 68.
All the even numbers between 61 and 73?
62 64 66 68 70 72
What is the mean mode and median of this data 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64?
step 1. arrange the numbers in ascending order (from low to high) as follows. was: 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64 now: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 step 2. count the number of the numbers above, or assign an index as follows. string: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 index: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 so the count is 20. The mode is the number most frequently observed. The mode is 65, which occurs four times. The median is the number in the middle. In this case, the 10th and 11th numbers both qualify for consideration. We take the average of the two numbers. The median is therefore 67. Alternate methods: 1) Use Microsoft Excel statistical functions of =mode() and =median() 2) Draw a bar graph with the horizontal axis of integers from 62 to 80. The y-axis is the frequency observed for that specific x value. For example, the frequency for 62 is one. The frequency for 63 is zero, and so on. The mode is the bar with the highest count. The median is not so obvious from a bar graph, unless the distribution is symmetric. Need some manual counting.
What is the median of 61 62 64 68 70 71 72?
It is 68, the number in the middle when they are arranged in order.
What is the median of 71 plus 67 plus 67 plus 72 plus 76 plus 73 plus 68 plus 72 plus 72?
I guess you mean: What is the median of the numbers 71, 67, 67, 72, 76, 73, 68, 72, 72? (because adding the numbers would yield a single number). The median is the middle number when the numbers are listed in order. Listing in order: 71, 67, 67, 72, 76, 73, 68, 72, 72 ⇒ 67, 67, 68, 71, 72, 72, 72, 73, 76 There are 9 numbers, so the middle number is the 5th one which is 72. If there had been an even number of numbers, there is no middle one so the median is the mean average of the middle two. Example: If there had been no 76, so the list contained: 67, 67, 68, 71, 72, 72, 72, 73 then there would be 8 numbers, so the median would be the mean average of the 4th and 5th numbers, namely: (71 + 72) ÷ 2 = 71.5
What is the median of 57 57 62 64 69 69 69 72 73 73 75 78 80 81?
There are 14 numbers - therefore, the median number is halfway between the seventh and eighth number. This is therefore 70.5.
What is the mean mode median of 64 64 64 65 65 65 65 67 67 68 68 70 70 72 73 76 79 80?
64 64 64 65 65 65 65 67 67 68 68 70 70 72 73 76 79 80. NB Place the numbers in RANK order. In this case it is already done #1 MODE ; is the term that occurs most frequently. In this case it is '65' , as there are four lots of '65' #2 MEDIAN ; is the term that occurs at the ABSOLUTE middle of the ranked order. Since there are eighteen terms, there is no absolute middle term. So we take the two middle terms that have the same number of terms to their side, that is terms nine & ten. They are 67 & 68. We then add these two together and halve the result. Hence (67 + 68) / 2 = 67.5. This is the median term. #3 MEAN ; is the sum of all the terms, which is the divided by the number of terms. Hence (64+64+64+65+65+65+65+67+67+68+68+70+70+72+73+76+79+80)/18 = 69' NB Another way of calculating the mean is ((3x64)+(4x65)+(2x67)+(2x68)+(2x70)+72+73+76+79+80)/18 = 69 NNB The word 'average' is casually used in the non-mathematical world, but the correct term is MEAN.
What is the median of the data set 60 70 69 65 62 70 72?
It is: 69
What is the median of 72 85 86 75 64 90 75 86?
80
How do you calculate the varience?
find varience fo rthis numbers 71, 67, 70, 59, 71, 68, 67, 71, 80, 68, 74, 69, 72, 68.
What is the odd one out 49 36 72 25 64?
49, 36, 25 and 64 are all squares of whole numbers. 64 = 82 49 = 72 36 = 62 25 = 52 The square root of 72 is not a whole number, but approximately 8.48. Thus 72 is the "odd one out".
What is the median of 54 and 72?
Median is: (54+72)/2 = 63.
All the even numbers between 61 and 73?
62 64 66 68 70 72
What is the mean of 58 64 66 67 70 73 73 74 83 92?
72
