64 64 64 65 65 65 65 67 67 68 68 70 70 72 73 76 79 80.
NB Place the numbers in RANK order. In this case it is already done
#1 MODE ; is the term that occurs most frequently. In this case it is '65' , as there are four lots of '65'
#2 MEDIAN ; is the term that occurs at the ABSOLUTE middle of the ranked order. Since there are eighteen terms, there is no absolute middle term. So we take the two middle terms that have the same number of terms to their side, that is terms nine & ten. They are 67 & 68. We then add these two together and halve the result. Hence (67 + 68) / 2 = 67.5. This is the median term.
#3 MEAN ; is the sum of all the terms, which is the divided by the number of terms. Hence
(64+64+64+65+65+65+65+67+67+68+68+70+70+72+73+76+79+80)/18 =
69'
NB Another way of calculating the mean is
((3x64)+(4x65)+(2x67)+(2x68)+(2x70)+72+73+76+79+80)/18 = 69
NNB The word 'average' is casually used in the non-mathematical world, but the correct term is MEAN.
No number appears more than all others, but 85, 86 and 96 all appear twice, and so they can all be said to be the mode.
The median is 50. Put the numbers in ascending numerical order: 40 45 48 52 61 65 For a set of numbers with an odd number of observations, the median would simply be the middle number. Because this set of numbers has an even number of observations, we take the middle two observations (48 and 52) and find their average. To find the average you add the observations and divide by the number of observations. In this case you would take 48 added to 52 and divide the sum of these numbers by 2. This gives you an answer of 50. (48 + 52 = 100 / 2 = 50)
If Larry gets a 70 on a physics test where the mean is 65 and the standard deviation is 5.8, where does he stand in relation to his classmates
IQ from 50 to 70 is 'Mild mental retardation'.
Steps:1.) Arrange the data either ascending or descending order of their values.2.) Determine the total number of observations, say n.3.) If the set of number is odd then the middle number will be the median. And if the set of number is even then mean of middle two numbers will be the median.a.) After that we'll be starting to discuss and give examples on how to find the median of ungrouped data.Example1:1.) Find the median of 12, 15, 10, 18, 8.2.) Arrange the data either ascending or descending order of their values.8, 10, 12, 15, 18(ascending)18, 15, 12, 10, 8(descending)3.) If the set of numbers is an odd integer, find the middle number in the set of numbers.From the above middle number 12 then 12 is the median.Example2:1.) Find the median of 23, 46, 18, 32, 65, 20.2.) Arrange the data either ascending or descending order of their values.18, 20, 23, 32, 46, 65(ascending)65, 46, 32, 23, 20, 18(descending)3.) If the set of numbers is an even integer, find the two middle numbers in the set of numbers.From the above we can say that there are two middle numbers23 and 32. So,Md = 23+32/2 = 27.5By: HuebosFb: Jupete02@yahoo.comTwitter: @kimjupetehuebos
56, 57, 64, 65, 66, 75, 76 Mean: 65 and 4/7 Median: 65 Mode: There is no mode. Range: 20
mean = (65 + 56 + 57 + 75 + 76 + 66 + 64)/7 = 65.57 median = "middle" number = 65 mode = most common number = all are equally common
The mode, median, and range of a single data point such as 65 are all the data point itself, 65 in this instance.
Mean: 67.143 Median: 78 Mode: 56, 78, 85, 92, 65, 79, 15 Range: 77
The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5
step 1. arrange the numbers in ascending order (from low to high) as follows. was: 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64 now: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 step 2. count the number of the numbers above, or assign an index as follows. string: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 index: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 so the count is 20. The mode is the number most frequently observed. The mode is 65, which occurs four times. The median is the number in the middle. In this case, the 10th and 11th numbers both qualify for consideration. We take the average of the two numbers. The median is therefore 67. Alternate methods: 1) Use Microsoft Excel statistical functions of =mode() and =median() 2) Draw a bar graph with the horizontal axis of integers from 62 to 80. The y-axis is the frequency observed for that specific x value. For example, the frequency for 62 is one. The frequency for 63 is zero, and so on. The mode is the bar with the highest count. The median is not so obvious from a bar graph, unless the distribution is symmetric. Need some manual counting.
Median is 70 The median is the middle number once you have reordered the sequence (therefore, 72 is not the median). The mode is the most common number The mean is the average.
59, 60, 60, 60, 62, 64, 65, 70, 71, 78 The median is 63.
65
Range: 24 Median: 59.5 Mode: 57, 61, 58, 54, 68, 51, 65, 75
Median = middle number = mean of 65 & 66 which is 65.5.
To find the mean, add up the numbers in the set and divide that total by 22 (the number of numbers there are) In a set with an even number of numbers, the median is the average of the middle two which appears to be 69.25 Since no number appears more often than any other, this set has no mode.