Well, there are various ways. The most simple way is to approximate the solution:
89 is between 9^2 and 10^2, therefore the first digit is 9
89 is between 9.4^2 and 9.5^2, therefore the second digit is 4
There is a second method. in which you use the Newton's method:
Consider the following equation: f(x)=x^2-89, which has sqrt[89] as its root.
Let x0 (the starting value) be 9.
This is the formula of Newton's method:
x_(n+1)= x_(n)- f(x_n)/f'(x_n)
x_(n+1)= x_(n)- (x_(n)^2-89)/2*(x_n)
Now we begin the approxiamton:
x_(2)= 9- (9^2-89)/(2*9)=9.4444
x_3=9.433
x_3=9.43398132
If you need digits, just use more iterations (The numbers of digits doubles for each iteration ).
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The square root of 89 is halfway between the square root of 81 = 9 and the square root of 100 = 10. Rounded to two decimal places, the square root of 89 is equal to 9.43.
9.4
sqrt(356) = sqrt(4*89) = sqrt(4)*sqrt(89) = 2*sqrt(89)
The square root of 7921 is 89.
Providing it's a right angle triangle use Pythagoras' theorem: 252+402 = 2225 and the square root of this is about 47.16990566 meters The exact answer is 5 times the square root of 89