I don't no
sjsjiajska
Midpoint = (x/2, y/2)
You could use algebra (see below for how to do that), or you could graph the line and measure it.Using algebraThe x-coordinate of the midpoint of a line segment is the average of the x-coordinates of the end-points. 1/2(-6 + 6) = 0The y-coordinate of the midpoint of a line segment is the average of the y-coordinates of the end-points.1/2(0 + 0) = 0The midpoint of the given horizontal segment is the origin, (0, 0) .
Not too sure of (410) because it could mean (4, 10) or (41, 0) But the midpoint is found by: (x1+x2)/2 and (y1+y2)/2 which will give the midpoint of (x, y)
The methods you could use to calculate the x-coordinate of the midpoint of a horizontal segment with endpoints at 0 0 and 20 0 would be: Divide 20 by 2 Count by hand -------------------------------------------------------------------------------------------------------------------- The easiest way to calculate the x-coordinate of the midpoint of any line segment is to add the x-coordinates of the end points together and divide by 2; similarly for the y-coordinates. In this case, the x-coordinate of the midpoint is (20 + 0)/2 = 20/2 = 5
Points: (0, 0) and (20, 0) Midpoint: (10, 0)
If you mean that the line segment endpoints are (-4, 0) and (7, 0) then the midpoint is (1.5, 0)
the midpoint
If you mean endpoints of (0, 0) and (0, 15) then the midpoint is at (0, 7.5)
The midpoint is (0, 1)
If you mean endpoints of (0, 0) and (0, -12) then the midpoint is (0, -6)
If you mean endpoints of (-6, 0) and (6, 0) then the midpoint is at the origin of (0, 0)
sjsjiajska
-2.5
Midpoint = (x/2, y/2)
Points: (-11, 0) and (9, -1) Midpoint: (-1, -1/2)
Midpoint of line from (4, 0) to (0, 2) is: ((4 + 0)/2, (0 + 2)/2) = (4/2, 2/2) = (2, 1)