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Let X be the lower number.

The problem is: minimize X(X+8).

Let Y=X(X+8)=X2+8X.

The vertex of this parabola is the minimum since it points up.

The X-coordinate of the vertex is -8/2 = -4.

So the minimum product is -4*4 = -16.

Note the two numbers here are -4 and 4.

Verify (using calculus)

dY/dX = 2X + 8 = 0 iff X = -8/2 = -4.

, implies Y = -16.

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Q: What is the minimum product of two numbers that differ by 8?
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