-2
It is a deficient number. The first abundant number is 12. 12: 1,2,3,4,6,12 which equal 28 28>(12*2) and the abundance is 28-(12*2)=4
To find the number halfway between any two numbers x and y, add x and y, then divide the answer by 2. So for 21 and 35, 21+ 35 = 56. 56/2 = 28. You can check your answer by seeing that 21 + 7 = 28 and 35 - 7 = 28.
588
28
16 + 12 = 28
23
The Answer is 26
To find the missing number in the sequence 10, 15, 28, we can look for a pattern in the differences between the numbers. The difference between 10 and 15 is 5, and the difference between 15 and 28 is 13. If we assume a pattern in the differences, the missing number could be 21, which fits as the average of 15 and 28. Thus, the sequence could be 10, 15, 21, 28.
LCM of 12 and 21 is 84, which is also a multiple of 28 so 84 is your answer.
21 and 28 are composite.
It is a deficient number. The first abundant number is 12. 12: 1,2,3,4,6,12 which equal 28 28>(12*2) and the abundance is 28-(12*2)=4
12: 1 2 3 4 6 7 12 14 21 28 42 84.
They are 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42 and 84.
The factors of 84 are 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42. 84.
28 is the answer. if 12 is 15% of a number ,the number is 80. 35% of 80 is 28
When figuring out what number goes both into 21 and 28, you should look at the factor paris. 21: 1 x 21, 3 x 7 28: 1, 28, 2 x 14, 4 x 7 7 goes into both 21 and 28.
x + (-12) = 28 So x = 28 + 12 = 40