-2
It is a deficient number. The first abundant number is 12. 12: 1,2,3,4,6,12 which equal 28 28>(12*2) and the abundance is 28-(12*2)=4
21
588
8 12 16
To find the number halfway between any two numbers x and y, add x and y, then divide the answer by 2. So for 21 and 35, 21+ 35 = 56. 56/2 = 28. You can check your answer by seeing that 21 + 7 = 28 and 35 - 7 = 28.
23
The Answer is 26
LCM of 12 and 21 is 84, which is also a multiple of 28 so 84 is your answer.
21 and 28 are composite.
It is a deficient number. The first abundant number is 12. 12: 1,2,3,4,6,12 which equal 28 28>(12*2) and the abundance is 28-(12*2)=4
12: 1 2 3 4 6 7 12 14 21 28 42 84.
The factors of 84 are 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42. 84.
They are 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42 and 84.
When figuring out what number goes both into 21 and 28, you should look at the factor paris. 21: 1 x 21, 3 x 7 28: 1, 28, 2 x 14, 4 x 7 7 goes into both 21 and 28.
28 is the answer. if 12 is 15% of a number ,the number is 80. 35% of 80 is 28
x + (-12) = 28 So x = 28 + 12 = 40
12/28