In the data 45, 48, 50, and 52 - there is no mode.
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Although, in statistical terms, all four values are modes.
It is like a race with 4 contestants. If all four breast the tape at exactly the same time would you say there are no winners or that all four are winners? Statistical rules governing the definition of modes go for all four being winners.
A single number, such has, 7152484654452062 can have only one mean, median, mode. And the range is 0.
52
48, 50, 52
48, 52, 56, 60, 64, 68
It is 52, the middle number when they are in order.
A single number, such has, 7152484654452062 can have only one mean, median, mode. And the range is 0.
44, 45, 46, 48, 49, 50, 51, 52 (including 52).
49
Whole numbers: 45, 46, 47, 48, 49, 50, 51, 52, 53, 54
45, 46, 47, 48, 49, 50, 51, 52, 53, 54 Ten of them.
Whole numbers: 45, 46, 47, 48, 49, 50, 51, 52, 53, 54
The median is 50. Put the numbers in ascending numerical order: 40 45 48 52 61 65 For a set of numbers with an odd number of observations, the median would simply be the middle number. Because this set of numbers has an even number of observations, we take the middle two observations (48 and 52) and find their average. To find the average you add the observations and divide by the number of observations. In this case you would take 48 added to 52 and divide the sum of these numbers by 2. This gives you an answer of 50. (48 + 52 = 100 / 2 = 50)
42 44 45 46 48 49 50 51 52
55, as it appears more than any other number in the list.
40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55
52
The mode is 36.