785. sequence multiplies number by 5 then minuses 3 on next go and repeats
160
20000 / 5 = 4000 4000 / 5 = 800 800 / 5 = 160 160 / 5 = 32
To find the nth term of a sequence, we first need to determine the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 7 each time. Therefore, the nth term can be represented by the formula Tn = 6 + 7(n-1), where n is the position of the term in the sequence.
The rest of the sequence would be as follows: 40, 20, 10, 5... because each successive number is half of the prior.
The odd numbers between 140 and 160 are 141, 143, 145, 147, 149, 151, 153, 155, and 157. Odd numbers are integers that are not divisible by 2, meaning they have a remainder of 1 when divided by 2. In this range, every other integer is odd, as even numbers are skipped.
151, 157.
160
How about: 157
40 5 10 20 40 80 160.......double the number each time.
160
160
Yes, each number is multiplied by 2 therefore the next 2 numbers in the sequence would be 80 & 160
74, according to the rule: Un = (3n4 - 38n3 + 177n2 - 270n + 160)/8, where n = 1, 2, 3, ...
The 40th number in the sequence will be 40 x 4, or 160.Reasoning:Because the sequence is multiples of 4.The 1st number in the sequence is 1 x 4, or 4.The 2nd number in the sequence is 2 x 4, or 8...The 4th number in the sequence is 4 x 4, or 16...The 17th number in the sequence is 17 x 4, or 68
151 157.
13 x 13 = 169
That's the prime factorization of 160.