Any number that you choose can be the next number. It is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest solution, based on a polynomial of order 5 is
t(n) = (-34n^5 + 565*n^4 - 3460*n^3 + 9575*n^2 - 11626*n + 5100)/60 for n = 1, 2, 3, ... and, accordingly, the next number in the sequence is 146.
240
22
The pattern in the sequence is multiplying the previous number by a factor that increases by 2 each time. Starting with 2, the next number is obtained by multiplying 2 by 2 (to get 4), then by 3 (to get 12), then by 4 (to get 48), and finally by 5 (to get 240). Therefore, the next number in the sequence would be 240 multiplied by 6, which equals 1440.
The next number in the sequence is 27.
One answer would be 0.There is a pattern of half the number and subtract 2. 4/2 - 2 = 0.
64
240
20
2
20
56
11
11
To get the next number in the sequence, you simply multiply by 26*2=1212*2=2424*2=4848*2=96
22
The pattern in the sequence is multiplying the previous number by a factor that increases by 2 each time. Starting with 2, the next number is obtained by multiplying 2 by 2 (to get 4), then by 3 (to get 12), then by 4 (to get 48), and finally by 5 (to get 240). Therefore, the next number in the sequence would be 240 multiplied by 6, which equals 1440.
The next number in the sequence is 27.