Any number (or numbers) that you choose can be next. It is easy to find a rule based on a polynomial of order 5 such that the first five numbers are as listed in the question followed by the chosen next numbers. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest rule, based on a polynomial of order 4 is
T(n) = (-7n^4 + 80n^3 - 314n^2 + 499n - 246)/6 for n = 1, 2, 3, ...
Accordingly, the next three numbers are -58, -251 and -677.
prime numbers - next number is 13
2(x2=) 4 3(x3=) 9 4(x4=)16 the next numbers are 16 5 25 6 36
1, 3, 4, 7, 11, 18, 29, 47
multiply by 1.1
115 130 135
what are the next numbers in the pattern 1, 2, 3, 5, 8, 13,_,_
8
prime numbers - next number is 13
42 123 243
Add the previous 2 numbers to get the next number.
2(x2=) 4 3(x3=) 9 4(x4=)16 the next numbers are 16 5 25 6 36
The next number is 13, the total of the two numbers preceding it.
12, 10 and 15 the are alternatively increased by 2 and 3
70, 80, 92.
1, 3, 4, 7, 11, 18, 29, 47
multiply by 1.1
115 130 135