Given any number it is easy to find a rule based on a polynomial of order 5 such that the first five numbers are as listed in the question and the nth is the given number. There are also non-polynomial solutions.
The simplest polynomial of smaller order is:
Un = (n2 + n + 4)/2 for n = 1, 2, 3, ...
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The nth term is 18 -3n and so the next term will be 3
t(n) = 5n - 3
3n
12 - 5(n-1)
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .