t(n) = 3*2n-1
Or just 3*2n
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If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
Looks like 57: 12+9=21, +9=30, +9=39, +9=48, +9=57.
Had it not been for 64, the nth term would be given by t(n) = 3*n2 However, this cannot be the case because then t(4) would have been 48, not 64.
t(n) = (5n3 - 30n2 + 85n - 48)/6 , n = 1, 2, 3, ...