If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
It goes up by (24-16) = 8 each time. The first time is 16. So the nth term is 8n + 8.
Looks like 57: 12+9=21, +9=30, +9=39, +9=48, +9=57.
Had it not been for 64, the nth term would be given by t(n) = 3*n2 However, this cannot be the case because then t(4) would have been 48, not 64.
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
3(2^n-1) * * * * * Nearly, but not quite. The correct answer is 3*2n
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If you mean: 8 28 48 and 68 then the nth term is 20n -12 and so the next number will be 88
It goes up by (24-16) = 8 each time. The first time is 16. So the nth term is 8n + 8.
> since the value rises by nine at each step and the first term is 12 the formula for > the nth term is: 12+(n-1)*9 Which simplifies to Sn = 9n + 3
Looks like 57: 12+9=21, +9=30, +9=39, +9=48, +9=57.
Had it not been for 64, the nth term would be given by t(n) = 3*n2 However, this cannot be the case because then t(4) would have been 48, not 64.
t(n) = (5n3 - 30n2 + 85n - 48)/6 , n = 1, 2, 3, ...
They are: 12, 24, 36 and 48
You are adding by 12. 12 + 12 = 24 24 + 12 = 36 36 + 12 = 48
The greatest common factor of the numbers 12, 24 and 48 is 12.The factors of 12 are 1,2,3,4,6,12The factors of 24 are 1,2,3,4,6,8,12,24The factors of 48 are 1,2,3,4,6,8,12,16,24,48so the greatest common factor is 12