The pattern between these numbers seems to be that they are incrementing by five each time. (9 - 4 = 5, 14 - 9 = 5, etc.) Also, the series starts at four.
So the formula to find the nth term for this series would be
5(n-1) + 4
For the first in the series to be four, the n being multiplied by the five must be zero, so that is why there is the minus one.
Testing the formula:
5(3-1) + 4 = 14 correct
5(5-1) + 4 = 24 correct
The nth term is (36 - 4n)
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...
29
Given ANY number at all, it is possible to find a cubic polynomial such that that particular number is the nth number in a sequence starting with the above three. The simplest rule, however, is Un = 5n + 9
The nth term is (36 - 4n)
If you mean: 6 12 18 24 then the nth term is 6n
24-5n
44
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
7n - 4