The pattern between these numbers seems to be that they are incrementing by five each time. (9 - 4 = 5, 14 - 9 = 5, etc.) Also, the series starts at four.
So the formula to find the nth term for this series would be
5(n-1) + 4
For the first in the series to be four, the n being multiplied by the five must be zero, so that is why there is the minus one.
Testing the formula:
5(3-1) + 4 = 14 correct
5(5-1) + 4 = 24 correct
The nth term is (36 - 4n)
It goes up by (24-16) = 8 each time. The first time is 16. So the nth term is 8n + 8.
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
The given sequence appears to be increasing by 10 each time. To find the nth term, we can use the formula for arithmetic sequences: nth term = first term + (n-1) * common difference. In this case, the first term is 4 and the common difference is 10. Therefore, the nth term for this sequence would be 4 + (n-1) * 10, which simplifies to 10n - 6.
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...
29
Given ANY number at all, it is possible to find a cubic polynomial such that that particular number is the nth number in a sequence starting with the above three. The simplest rule, however, is Un = 5n + 9
The nth term is (36 - 4n)
If you mean: 6 12 18 24 then the nth term is 6n
24-5n
It goes up by (24-16) = 8 each time. The first time is 16. So the nth term is 8n + 8.
44
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
The given sequence appears to be increasing by 10 each time. To find the nth term, we can use the formula for arithmetic sequences: nth term = first term + (n-1) * common difference. In this case, the first term is 4 and the common difference is 10. Therefore, the nth term for this sequence would be 4 + (n-1) * 10, which simplifies to 10n - 6.
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .