The question cannot be answered without assuming that
(a) the figure is a polygon and
(b) it is regular.
There is absolutely nothing in the question to justify making these assumption but since there cannot be any answer other wise, let us assume that they are valid. Then
Interior angle = 171 implies that each exterior angle is 180-171 = 9%
The sum of all axterior angles is 360 degrees.
If the polygon has n sides, then 360/n = 9 so that n = 40.
Therefore the shape if it is a regular polygon, has 40 sides.
If each interior angle is 171 degrees then each exterior angle is 180-171 = 9 degrees. Sum of all exterior angles (irrespective of number of sides) is 360 degrees So number of sides = 360/9 = 40
Forty of them.
An Obtuse Angle is more than 90° but less than 180°
171 - 38 = 133 so 133 + 38 sum to 171
The formula to find the sum of the angles of a polygon is: 180(n - 2) Since we know that one angle of this regular polygon is 171 degrees, we can find what kind of polygon it will be, using the formula: 180(n - 2) = 171n 180n - 360 = 171n 180n - 171n = 360 9n = 360 n = 360/9 n = 40 Thus the polygon is a 40-sided polygon. Check: 180(40 - 2) = 180(38) = 6840, which is the sum of the angles of the polygon. 6840/40 = 171 degrees, which is the measure of one of the angles of that polygon .
It has 40 sides 180-171=9 360/9=40
40 sides
If each interior angle is 171 degrees then each exterior angle is 180-171 = 9 degrees. Sum of all exterior angles (irrespective of number of sides) is 360 degrees So number of sides = 360/9 = 40
40 sides
40 sides
It will have 40 sides
The interior angle of a regular polygon with x sides is 180(x-2)/x. Rearranging the formula for x, the number of sides for a shape with y angles is 360/(180-y). From this formula, the number of sides is 40.
If it's a regular polygon then it will have 40 sides
Forty of them.
divide the number of sides by 171
a pentagon has 5 sides. the formula to figuring out how many sides it has is (n-2)180. therefore the sum of the sides is 540.
It is 171 degrees