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The question cannot be answered without assuming that

(a) the figure is a polygon and

(b) it is regular.

There is absolutely nothing in the question to justify making these assumption but since there cannot be any answer other wise, let us assume that they are valid. Then

Interior angle = 171 implies that each exterior angle is 180-171 = 9%

The sum of all axterior angles is 360 degrees.

If the polygon has n sides, then 360/n = 9 so that n = 40.

Therefore the shape if it is a regular polygon, has 40 sides.

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Q: What is the number of sides with the interior angle of 171?
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The number of sides if the polygon's interior angle is 171 degrees?

It has 40 sides 180-171=9 360/9=40


If the measure of each interior angle of a regular polygon is 171 find the number of sides in the polygon?

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How many sides does a regular polygon have if the measure of the angle is 171?

If each interior angle is 171 degrees then each exterior angle is 180-171 = 9 degrees. Sum of all exterior angles (irrespective of number of sides) is 360 degrees So number of sides = 360/9 = 40


How many sides does a polygon have if each interior angle measures 171?

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How many sides does a polygon have if each interior angle equals 171?

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Work out the number of sides of a regular polygon with an interior angle of 171 degrees?

The interior angle of a regular polygon with x sides is 180(x-2)/x. Rearranging the formula for x, the number of sides for a shape with y angles is 360/(180-y). From this formula, the number of sides is 40.


What polygon has an interior Angle of 171?

If it's a regular polygon then it will have 40 sides


If a polygon has 171 interior angle how many sides has it got?

Forty of them.


What is the number of side of a regular polygon if one angle measures 171?

divide the number of sides by 171


How many sides would a regular pentagon have if it's interior angle was 171 degrees?

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What is the measure of one interior angle of a regular 40 gon?

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