there are 5 significant figures
0.320g has three significant figures. A significant figure is any non-zero digit or any embedded or trailing zero. Leading zeros are not significant.
Two significant figures the measurment 0.0255 g should be reported as 0.026g
2 significant figures.
5 of them.
Three.
To find the product of 3.25 g and 4.145 g, you multiply the two values, which equals 13.487125 g. However, the result should be expressed with the correct number of significant figures. Since 3.25 g has three significant figures and 4.145 g has four significant figures, the product should be rounded to three significant figures, resulting in 13.5 g.
The product of 0.12 g, 1.8 g, and 0.562 g should have the same number of significant figures as the measurement with the fewest significant figures, which is 0.12 g in this case. Therefore, the product should be expressed with two significant figures.
There are 3 significant figures in 0.0000246 g.
That measurement has 4 significant figures. It could also be stated as 1.580 x 10^-3.
The measurement of 417.32 g has five significant figures. Each non-zero digit and any zeros between them are considered significant in a decimal number.
When rounded to four significant figures, 417.32 g would be 417.3 g.
0.320g has three significant figures. A significant figure is any non-zero digit or any embedded or trailing zero. Leading zeros are not significant.
0.0645g to two significant figures is 0.065g
There are 2 significant figures in this measurement.
143 g has three significant figures. The leading zeros are not considered significant.
52 g Be x 1 mol/9 g = 5.8 moles (2 significant figures)
To find the average of the three masses (9.93 g, 9.90 g, and 10.02 g), first sum the values: 9.93 + 9.90 + 10.02 = 29.85 g. Next, divide by the number of measurements: 29.85 g / 3 = 9.95 g. Since the least precise measurement (9.90 g) has three significant figures, the average should also be expressed to three significant figures, resulting in an average mass of 9.95 g.