Cubes of digits 1 - 4
n3. (nxnxn) 13 = 1, 23 = 8, 33 = 27...
1x1x1 = 1
2x2x2 = 8
3x3x3 = 27
4x4x4 = 64
5x5x5 = 125
6x6x6 = 216
343.
64 should be in between 27 and 125.
It looks like 64 is the most likely answer.. There might be other patterns that I don't see. 13 23 33 43 1 8 27 64
13 ...23 ...33 ...43 ...53=125■
They are the cubes of the natural numbers, starting with 1.
64
125 (the sequence is successive numbers cubed)
The given sequence consists of the cubes of the natural numbers: (1^3 = 1), (2^3 = 8), and (3^3 = 27). Following this pattern, the next number would be (4^3 = 64). Therefore, the missing number in the sequence is 64.
64. It's the sequence f(n) = n^3
343.
64 should be in between 27 and 125.
The sequence consists of the cubes of consecutive integers: (1^3 = 1), (2^3 = 8), (3^3 = 27), (4^3 = 64), (5^3 = 125), and (6^3 = 216). Therefore, the missing number in the sequence is 64.
These are perfect cubes (of 1, 2 and 3) so the next two are 64 and 125
The missing numbers in the sequence are 1, 8, 27, and 64, which correspond to the cubes of the integers 1, 2, 3, and 4, respectively. The next number in the sequence would be 125, which is the cube of 5 (5^3). To identify this, I recognized the pattern of perfect cubes in the sequence.
It looks like 64 is the most likely answer.. There might be other patterns that I don't see. 13 23 33 43 1 8 27 64
13 ...23 ...33 ...43 ...53=125■
64 because it is basically cube each number in a row.