Cubes of digits 1 - 4
n3. (nxnxn) 13 = 1, 23 = 8, 33 = 27...
1x1x1 = 1
2x2x2 = 8
3x3x3 = 27
4x4x4 = 64
5x5x5 = 125
6x6x6 = 216
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343.
64 should be in between 27 and 125.
It looks like 64 is the most likely answer.. There might be other patterns that I don't see. 13 23 33 43 1 8 27 64
13 ...23 ...33 ...43 ...53=125■
They are the cubes of the natural numbers, starting with 1.
64
125 (the sequence is successive numbers cubed)
64. It's the sequence f(n) = n^3
343.
64 should be in between 27 and 125.
These are perfect cubes (of 1, 2 and 3) so the next two are 64 and 125
It looks like 64 is the most likely answer.. There might be other patterns that I don't see. 13 23 33 43 1 8 27 64
13 ...23 ...33 ...43 ...53=125■
64 because it is basically cube each number in a row.
They are the cubes of the natural numbers, starting with 1.
1 8 27 64 125 216 343
The sequence 1, 8, 27, 64 represents the cubes of the natural numbers 1, 2, 3, and 4 respectively. In mathematical terms, this sequence follows the rule of n^3, where n represents the position of the number in the sequence. Therefore, the rule for this sequence is n^3, where n starts at 1 and increments by 1 for each subsequent number.