Cubes of digits 1 - 4
n3. (nxnxn) 13 = 1, 23 = 8, 33 = 27...
1x1x1 = 1
2x2x2 = 8
3x3x3 = 27
4x4x4 = 64
5x5x5 = 125
6x6x6 = 216
343.
64 should be in between 27 and 125.
It looks like 64 is the most likely answer.. There might be other patterns that I don't see. 13 23 33 43 1 8 27 64
13 ...23 ...33 ...43 ...53=125■
They are the cubes of the natural numbers, starting with 1.
64
125 (the sequence is successive numbers cubed)
64. It's the sequence f(n) = n^3
343.
64 should be in between 27 and 125.
The sequence consists of the cubes of consecutive integers: (1^3 = 1), (2^3 = 8), (3^3 = 27), (4^3 = 64), (5^3 = 125), and (6^3 = 216). Therefore, the missing number in the sequence is 64.
These are perfect cubes (of 1, 2 and 3) so the next two are 64 and 125
It looks like 64 is the most likely answer.. There might be other patterns that I don't see. 13 23 33 43 1 8 27 64
13 ...23 ...33 ...43 ...53=125■
64 because it is basically cube each number in a row.
The sequence given consists of the cubes of consecutive integers: (1^3 = 1), (2^3 = 8), (3^3 = 27), and (4^3 = 64). Therefore, the next number in the sequence is (5^3 = 125).
They are the cubes of the natural numbers, starting with 1.