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There are infinitely polynomials of order 3 that will give these as the first three numbers and any one of these could be "the" rule. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
For example,
t(n) = (-7n^3 + 42n^2 - 65n + 36)/6 gives the sequence 1, 3, 5, 0, ...
t(n) = -1n^3 + 6n^2 - 9n + 5 gives the sequence 1, 3, 5, 1, ...
t(n) = (-1n^3 + 6n^2 - 5n + 3)/3 gives the sequence 1, 3, 5, 5, ...
t(n) = (31n^3 - 186n^2 + 345n - 188)/2 gives the sequence 1, 3, 5, 100, ...
Each one is a valid answer!
The simplest solution, based on a polynomial or order 1 is
t(n) = 2n - 1 for n = 1, 2, 3
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What number comes next in this sequence 1 1 3 5?
8
The number which best completes the sequence below is1 1 3 2 4 6 5 25?
The number which best completes the sequence below is:1 1 3 2 4 6 5 25 ?
What is the missing number in the sequence shown below 1 2 3 5 13 21?
The sequence is 1,2,3,5,8,13,21.......8 is the missing number. This is known as a Fibonacci Sequence. The first two numbers are supplied and then further numbers in the sequence are formed from the sum of the two prior numbers. 3 = 1 + 2 5 = 2 + 3 8 = 3 + 5.....and so on.
What is the next number in this sequence 1 1 2 3 5?
Each number is being added to the one before it. So, 5+3=8. 8 is the next number.
What is the next number in the sequence 1 4 3 6 5 8?
7
