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[x = -4, y = 3]. There is more than 1 way to solve. Here's one:

  • multiply second equation by 4: -8x - 8y = 8
  • add to first equation {eliminating y}: -12x = 48
  • divide this by -12: x = -4.

Now substitute x = -4 into either of the original equations:

  • -2(-4) - 2y = 2
  • 8 - 2y = 2 ---> -2y = -6 ---> y = 3.

Check in the other equation: -4(-4) + 8(3) = 16 + 24 = 40 [checks out]

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