Wiki User
∙ 13y agoThe C2H2 us being oxidized, electrons stripped away, and the oxygen is being reduced, accepting electrons and in this case, carbon and hydrofen are coming along for the ride.
Wiki User
∙ 13y agoThis is an oxidation-reduction reaction.
Yep
It is an eothermic type of reaction.
C2h2+3o2=2c02+2h2o+2c
Calcium and water react to form calcium hydroxide and hydrogen. Ca + 2H2O --> Ca(OH)2 + H2
This is an oxidation-reduction reaction.
The balanced equation for the complete oxidation of acetylene (C2H2) burning in air is: 2C2H2 + 5O2 -> 4CO2 + 2H2O. This equation shows that two molecules of acetylene react with five molecules of oxygen to produce four molecules of carbon dioxide and two molecules of water.
The balanced equation for the complete combustion of ethyne (C2H2) is: 2C2H2 + 5O2 -> 4CO2 + 2H2O
The chemical equation shown is the combustion of ethyne (C2H2) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). The balanced equation is: 2C2H2 + 5O2 -> 4CO2 + 2H2O
Equations that separate the oxidation from the reduction parts of the reaction
The balanced equation for the combustion of acetylene (C2H2) in air to form carbon dioxide (CO2) and water (H2O) is: 2C2H2 + 5O2 -> 4CO2 + 2H2O
there are many possible combinations, as incomplete combustion refers only to the combustion of a fuel whereby not all of a fuel's carbon and hydrogen is converted to carbon dioxide and water, usually other products involve carbon particulates (C) or carbon monoxide (CO) as such two possible equations are:C2H4 + O2 => C2 + 2H20C2H4 + 2O2 => 2CO + 2H2O
First we have to figure out which species is oxidized and which is reduced and balance it in acid solution. On the left side, Ag has an oxidation number of 0 (it is an uncombined element). On the right side, Ag is +1. Why? Ag = +1 + 2CN- = -2 ----------------------------- Ag(CN) ion charge = -1 Note that oxygen on the left side also has an oxidation number of 0 for the same reason as Ag. But on the right side of the equation, it has formed H2O and has a charge of -2. CN- is really a spectator ion (isn't oxidized or reduced) so we can ignore it for now. Let's balance each half-reaction. I'm using = as an arrow sign. Oxidation: Ag = Ag+ + e- (done) Reduction: O2 = H2O Put a 2 in front of H2O O2 = 2H2O to balance oxygen Put 4H+ on the left side O2 + 4H+ = 2H2O to balance hydrogen Put 4e- on the left to O2 + 4H+ + 4e- = 2H2O To add the oxidation and reduction reactions together, I need to multiply the oxidation reaction by 4 so its electrons will cancel with the four that are in the reduction reaction. Doing that you get 4Ag + O2 + 4H+ = 4Ag+ + 2H2O In alkaline solution, you find the H+ above and add an equal number of OH- to BOTH sides of the equation: The 4H+ + 4OH- give 4 H2O. 4Ag + O2 + 4H+ = 4Ag+ + 2H2O +4OH- + 4OH- --------------------------------------... 4H2O If I delete two H2O from each side I get: 4Ag + O2 + 2H2O = 4Ag+ + 4OH- Finally, I can add 2CN- to each side for this: 4Ag + O2 + 2H2O + 8CN- = 4Ag(CN)- + 4OH-
Yep
As far as I can gather from mark schemes of A level papers... Hydrogenation is simply ADDING HYDROGEN, whereas reduction is removing O2 for example and replacing it with H2 Example: In this test paper, the marks are given for Hydrogenation ONLY, not reduction: H2C=CH2 + H2 --> CH3CH3 In this test paper, the marks are given for reduction ONLY, and not hydrogenation: C6H5NO2 + 3H2 --> C6H5NH2 + 2H2O (NitroBenzene) (AminoBenzene/phenylamine) This is just interpretation of the mark scheme, not concrete proof.
The reaction you provided is the decomposition of hydrogen peroxide into water and oxygen gas. This is a decomposition reaction where a single compound breaks down into two or more simpler substances.
exothermic