The C2H2 us being oxidized, electrons stripped away, and the oxygen is being reduced, accepting electrons and in this case, carbon and hydrofen are coming along for the ride.
This is an oxidation-reduction reaction.
Yep
It is an eothermic type of reaction.
C2h2+3o2=2c02+2h2o+2c
Calcium and water react to form calcium hydroxide and hydrogen. Ca + 2H2O --> Ca(OH)2 + H2
This is an oxidation-reduction reaction.
2c2h2+5o2=4co2+2h2o.
It is the balanced equation for the combustion of acetylene (or ethyne).
Ethyne is C2H2 2C2H2 + 5O2 ---> 2H2O + 4CO2
ΔS is negative and ΔG is negative at low temperatures...
5O2 + 2C2H2 --> 4CO2 + 2H2O + Qoxygen + acetylene -> carbon dioxide + water + heat-energy
there are many possible combinations, as incomplete combustion refers only to the combustion of a fuel whereby not all of a fuel's carbon and hydrogen is converted to carbon dioxide and water, usually other products involve carbon particulates (C) or carbon monoxide (CO) as such two possible equations are:C2H4 + O2 => C2 + 2H20C2H4 + 2O2 => 2CO + 2H2O
Na2[Fe(CN)5NO]·2H2O, the oxidation number of iron is +3.
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
Sodium - it goes from oxidation number 0 to +1
2H2O2 <-> H2O + O2 the oxidation number of each O in H2O2 is -1 the oxidation number in H2O is -2 the oxidation number in O2 is zero. The average oxidation number of oxygen atoms on both sides of the equation. is the same. So overall the net change to oxygen is zero one is reduced two are oxidised. Looked at from the viewpoint of the oxygen atoms in O2 they started off with oxidation number of -1 and have ended up with 0, so they have been oxidised. (oxidation is loss of electrons, and therefore an increase in oxidation number.)
Yep