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What else can I help you with?
What type of reaction is N2H4 plus 3O2 equals 2NO2 plus 2H2O?
This is an oxidation-reduction reaction.
2Li plus 2H2O equals 2LiOH plus H2?
Yep
What kind of chemical reaction is 2Na plus 2H2O equals 2NaOH plus H2?
It is an eothermic type of reaction.
Balance equation of acetylene plus oxygen equals carbon dioxide plus water vapor?
C2h2+3o2=2c02+2h2o+2c
Calcium plus H2O equals Hydrogen?
Calcium and water react to form calcium hydroxide and hydrogen. Ca + 2H2O --> Ca(OH)2 + H2
What type of reaction is N2H4 plus 3O2 equals 2NO2 plus 2H2O?
This is an oxidation-reduction reaction.
What type of Balanced equation for the complete oxidation reaction that occurs when acetylene C2H2 burns in air?
The balanced equation for the complete oxidation of acetylene (C2H2) burning in air is: 2C2H2 + 5O2 -> 4CO2 + 2H2O. This equation shows that two molecules of acetylene react with five molecules of oxygen to produce four molecules of carbon dioxide and two molecules of water.
What is the balanced equation for the complete combustion of Ethyne?
The balanced equation for the complete combustion of ethyne (C2H2) is: 2C2H2 + 5O2 -> 4CO2 + 2H2O
What is 2c2h2 5o2-4co2 2h2o?
The chemical equation shown is the combustion of ethyne (C2H2) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). The balanced equation is: 2C2H2 + 5O2 -> 4CO2 + 2H2O
Which balanced equation represents an oxidation-reduction reaction?
Equations that separate the oxidation from the reduction parts of the reaction
What is the half reaction for the oxidation of water?
The half reaction for the oxidation of water is: 2H2O - O2 4H 4e-
How do you write the formula when acetylene burns in air to form carbon dioxide and water?
The balanced equation for the combustion of acetylene (C2H2) in air to form carbon dioxide (CO2) and water (H2O) is: 2C2H2 + 5O2 -> 4CO2 + 2H2O
What is the chemical Equation for incomplete combustion of ethene?
there are many possible combinations, as incomplete combustion refers only to the combustion of a fuel whereby not all of a fuel's carbon and hydrogen is converted to carbon dioxide and water, usually other products involve carbon particulates (C) or carbon monoxide (CO) as such two possible equations are:C2H4 + O2 => C2 + 2H20C2H4 + 2O2 => 2CO + 2H2O
2Li plus 2H2O equals 2LiOH plus H2?
Yep
What is the reduction of water equation?
The reduction of water equation is the chemical reaction in which water is broken down into its elements, hydrogen and oxygen. This process is represented by the equation: 2H2O - 2H2 O2.
What is the reaction for Ag plus O2 AgO?
First we have to figure out which species is oxidized and which is reduced and balance it in acid solution. On the left side, Ag has an oxidation number of 0 (it is an uncombined element). On the right side, Ag is +1. Why? Ag = +1 + 2CN- = -2 ----------------------------- Ag(CN) ion charge = -1 Note that oxygen on the left side also has an oxidation number of 0 for the same reason as Ag. But on the right side of the equation, it has formed H2O and has a charge of -2. CN- is really a spectator ion (isn't oxidized or reduced) so we can ignore it for now. Let's balance each half-reaction. I'm using = as an arrow sign. Oxidation: Ag = Ag+ + e- (done) Reduction: O2 = H2O Put a 2 in front of H2O O2 = 2H2O to balance oxygen Put 4H+ on the left side O2 + 4H+ = 2H2O to balance hydrogen Put 4e- on the left to O2 + 4H+ + 4e- = 2H2O To add the oxidation and reduction reactions together, I need to multiply the oxidation reaction by 4 so its electrons will cancel with the four that are in the reduction reaction. Doing that you get 4Ag + O2 + 4H+ = 4Ag+ + 2H2O In alkaline solution, you find the H+ above and add an equal number of OH- to BOTH sides of the equation: The 4H+ + 4OH- give 4 H2O. 4Ag + O2 + 4H+ = 4Ag+ + 2H2O +4OH- + 4OH- --------------------------------------... 4H2O If I delete two H2O from each side I get: 4Ag + O2 + 2H2O = 4Ag+ + 4OH- Finally, I can add 2CN- to each side for this: 4Ag + O2 + 2H2O + 8CN- = 4Ag(CN)- + 4OH-
Oxidation reaction vs reduction reaction?
As far as I can gather from mark schemes of A level papers... Hydrogenation is simply ADDING HYDROGEN, whereas reduction is removing O2 for example and replacing it with H2 Example: In this test paper, the marks are given for Hydrogenation ONLY, not reduction: H2C=CH2 + H2 --> CH3CH3 In this test paper, the marks are given for reduction ONLY, and not hydrogenation: C6H5NO2 + 3H2 --> C6H5NH2 + 2H2O (NitroBenzene) (AminoBenzene/phenylamine) This is just interpretation of the mark scheme, not concrete proof.
