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The C2H2 us being oxidized, electrons stripped away, and the oxygen is being reduced, accepting electrons and in this case, carbon and hydrofen are coming along for the ride.

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Q: What is the oxidation and reduction in 2C2H2 plus 5O2 equals 4CO2 plus 2H2O?
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What type of reaction is N2H4 plus 3O2 equals 2NO2 plus 2H2O?

This is an oxidation-reduction reaction.

What type of Balanced equation for the complete oxidation reaction that occurs when acetylene C2H2 burns in air?

The balanced equation for the complete oxidation of acetylene (C2H2) burning in air is: 2C2H2 + 5O2 -> 4CO2 + 2H2O. This equation shows that two molecules of acetylene react with five molecules of oxygen to produce four molecules of carbon dioxide and two molecules of water.

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What is the chemical Equation for incomplete combustion of ethene?

there are many possible combinations, as incomplete combustion refers only to the combustion of a fuel whereby not all of a fuel's carbon and hydrogen is converted to carbon dioxide and water, usually other products involve carbon particulates (C) or carbon monoxide (CO) as such two possible equations are:C2H4 + O2 => C2 + 2H20C2H4 + 2O2 => 2CO + 2H2O

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Which element increases its oxidation number in the following reaction 2na plus 2h2o---2naoh plus h2?

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What kind of reaction is 2H2O2 2H2O plus O2?

2H2O2 <-> H2O + O2 the oxidation number of each O in H2O2 is -1 the oxidation number in H2O is -2 the oxidation number in O2 is zero. The average oxidation number of oxygen atoms on both sides of the equation. is the same. So overall the net change to oxygen is zero one is reduced two are oxidised. Looked at from the viewpoint of the oxygen atoms in O2 they started off with oxidation number of -1 and have ended up with 0, so they have been oxidised. (oxidation is loss of electrons, and therefore an increase in oxidation number.)

What is the reaction for Ag plus O2 AgO?

First we have to figure out which species is oxidized and which is reduced and balance it in acid solution. On the left side, Ag has an oxidation number of 0 (it is an uncombined element). On the right side, Ag is +1. Why? Ag = +1 + 2CN- = -2 ----------------------------- Ag(CN) ion charge = -1 Note that oxygen on the left side also has an oxidation number of 0 for the same reason as Ag. But on the right side of the equation, it has formed H2O and has a charge of -2. CN- is really a spectator ion (isn't oxidized or reduced) so we can ignore it for now. Let's balance each half-reaction. I'm using = as an arrow sign. Oxidation: Ag = Ag+ + e- (done) Reduction: O2 = H2O Put a 2 in front of H2O O2 = 2H2O to balance oxygen Put 4H+ on the left side O2 + 4H+ = 2H2O to balance hydrogen Put 4e- on the left to O2 + 4H+ + 4e- = 2H2O To add the oxidation and reduction reactions together, I need to multiply the oxidation reaction by 4 so its electrons will cancel with the four that are in the reduction reaction. Doing that you get 4Ag + O2 + 4H+ = 4Ag+ + 2H2O In alkaline solution, you find the H+ above and add an equal number of OH- to BOTH sides of the equation: The 4H+ + 4OH- give 4 H2O. 4Ag + O2 + 4H+ = 4Ag+ + 2H2O +4OH- + 4OH- --------------------------------------... 4H2O If I delete two H2O from each side I get: 4Ag + O2 + 2H2O = 4Ag+ + 4OH- Finally, I can add 2CN- to each side for this: 4Ag + O2 + 2H2O + 8CN- = 4Ag(CN)- + 4OH-