Each number is 15 fewer than the previous number
185-15=170 170/2=85 85+15=100 100+85=185 So the numbers are 100 and 85.
There are no two such numbers. 185 is equal to 185. No other number is equal to 185.
All multiples of 185 are divisible by it.
Any of its factors
numbers are 37 and 5
185-15=170 170/2=85 85+15=100 100+85=185 So the numbers are 100 and 85.
It is: 180+170+185+165 = 700/4 = 175 which is the average
170 to 185
(125 + 185)/2 = 310/2 = 165
There are no two such numbers. 185 is equal to 185. No other number is equal to 185.
166; 170; 170; 171; 175; 177; 180; 180; 182; 183; 184; 185; 188; 189
All multiples of 185 are divisible by it.
Definitely no.
Let a and b represent the numbers. ab = 185 a + b = 42 From this get b = 42 - a. Substitute into ab = 185. a(42 - a) = 185 -a2 + 42a - 185 = 0 a2 - 42a + 185 = 0 Factoring, we get (a - 5)(a - 37) = 0 Therefore the two numbers are 5 and 37.
152, 153, 154, 155, 156, 158, 159, 160, 161, 162, 164, 165, 166, 168, 169, 170, 171, 172, 174, 175, 176, 177, 178, 180, 182, 183, 184, 185, 186, 187, 188, 189, 190, 192, 194, 195, 196, 198
The numbers which end in 5 are: 105 115 125 135 145 155 165 175 185 195 205 215 225 235 245 255 265 275 285 295 This is a total of 20 numbers.
150, 152, 153, 154, 155, 156, 158, 159, 160, 161, 162, 164, 165, 166, 168, 169, 170, 171, 172, 174, 175, 176, 177, 178, 180, 182, 183, 184, 185, 186, 187, 188, 189, 190, 192, 194, 195, 196, 198, 200