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Find the molecular weight of potassium chlorate, which is approximately: 122.6 g/mol (K @39.1 g/mol + Cl @ 35.5 g/mol; O @ 3 x16.0 g/mol)

Now divide the molecular weight of potassium (K) by the total molecular weight of the compound to get the % composition of potassium in 1 molecule of potassium chlorate.

(39.1 g/mol)/(122.6 g/mol) * 100% = 31.9% or 32%

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Q: What is the percent composition in KCLO3 to the nearest whole number of potassium?
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