Molar mass of all oxygen in compound/Total molar mass of compound * 100
= % oxygen in compound
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Oh, dude, math time! So, to find the percentage, you just divide 35 by 45, which gives you 0.777777... Then you multiply that by 100 to get the percentage, which is 77.777777... but who's counting, right? So, technically, 35 out of 45 is 77.78%. Like, close enough, am I right?
Honey, lines AB and BA are like two peas in a pod - they're the same darn thing! In geometry, the order of the points on a line doesn't matter, so whether you call it line AB or line BA, it's all just one straight shot from point A to point B. So, yes, line AB is indeed the same as line BA.
1/1000 = .001 = 0.1%
To calculate the percentage of 500 out of a million, you would divide 500 by a million, which equals 0.0005. To convert this decimal to a percentage, you would multiply by 100, giving you 0.05%. Therefore, 500 out of a million is equal to 0.05%.
Oh, dude, you're hitting me with some math! Two fifths is the same as 40% because you just multiply the fraction by 100 to get the percentage. It's like converting your GPA to a cool percentage, but way easier. So, yeah, two fifths is 40%.
The compound Ba(OH)2 · 8H2O consists of one barium atom, two oxygen atoms from the OH groups, and 16 oxygen atoms from the water molecules. The total 18 oxygen atoms in the compound correspond to 72% of the total molecular weight.
The compound Ba(OH)2·8H2O has 8 water molecules associated with it. To find the percentage of water in the compound, calculate the molar mass of the water molecules (8H2O) and the molar mass of the entire compound (Ba(OH)2·8H2O). Then divide the molar mass of the water by the molar mass of the entire compound and multiply by 100 to get the percentage of water.
The chemical formula for barium hydroxide octahydrate is Ba(OH)2•8H2O.
Ba(OH)2·8H2O Barium Hydroxide Octahydrate Ba(OH)2·8H2O
The relative molecular weight of the compound nickel (II) sulphate heptahydrate NiSO4 7H2O is 280. 86. The total mass of oxygen in the compound is 176 g. Therefore the total percentage of oxygen to the nearest tenth is 60 percent
Barium hydroxide octahydrate, often written as Ba(OH)2·8H2O, is a chemical compound that consists of one barium ion (Ba2+) and two hydroxide ions (OH-) surrounded by eight water molecules. This compound is commonly used in laboratories as a strong base and in certain industrial processes.
Ba(OH)2.8H2O=315.51 8H2O=8x18.02=144.16 ?=144.16/315.51x100=45.69%
Formula: Na2B4O7·10H2O or Na2[B4O5(OH)4]·8H2O
Yes. The formula is Na2[B4O5(OH)4]·8H2O
Ba(OH)2 is the chemical formula barium hydroxide.
Ba(OH)2is the chemical formula of barium hydroxide.
Ba is Barium, OH is Hydroxide and the 8 H2O is Octahydrate. This results in Barium Hydroxide Octahydrate.