496 An integer is a perfect number if it is equal to the sum of its positive divisors - not including itself. 496 = 1 + 2 + 4 + 8 + 16 + 31 + 62 + 124 + 248.
It is: 490+10 = 500
There is only one Perfect Number within this range : 496. If 2ⁿ - 1 is prime then 2ⁿ⁻¹(2ⁿ - 1) is a perfect number. In this instance n = 5 then, 2⁴(2⁵ - 1) = 16 x 31 = 496...........and 31 is a prime number.
500
I dunno what yime period but he was born between 580 and 572 BC and died between 500 and 490 BC. hope this helps x
496 An integer is a perfect number if it is equal to the sum of its positive divisors - not including itself. 496 = 1 + 2 + 4 + 8 + 16 + 31 + 62 + 124 + 248.
It is: 490+10 = 500
Step-by-step explanation: The greatest number between 200 and 500 that is divisible by 7 is 497. So the multiples of 7 in this range are 203, 210, 217, 224, … 490, 497.
The Roman numeral CDXC represents the number 490. C (100) is subtracted from D (500) to give 400, and XC (90) is added to 400 to get 490.
500
On Converting between Arabic and Roman Numbers we get: 490 in roman numerals is written as : CDXC where 400=CD XC=90.
489.612 rounded to the nearest whole number = 490
485
That is improperly formed. It could be interpreted as 490 (500 - 10)
There is only one Perfect Number within this range : 496. If 2ⁿ - 1 is prime then 2ⁿ⁻¹(2ⁿ - 1) is a perfect number. In this instance n = 5 then, 2⁴(2⁵ - 1) = 16 x 31 = 496...........and 31 is a prime number.
it is 494 D=500 XD=490 V=5 IV=4 XDIV=494
That number rounds to 490 or 500. Numbers from 1-4 round downwards and number 5-9 round upwards.