well the formula is p=2(l+w) p stands for perimeter l stands for length w stands for width P= l+l+w+w =5+5+3+3 = 16
Perimeter = 2*(L+W) = 2*(3+7) = 2*10 = 20 yards. By the way, conventionally, the length is the bigger dimension.
3 ft = 1 yd → 5 ft = 1 yd 2 ft → 8 yd + 5 ft = 8 yd + 1 yd 2 ft = 9 yd 2 ft.
Well, L=6 and W=18If you do the math you get (6*2)+(18*2)=12+36=48Your final answer 48 yd. The perimeter is 48 yd.
There are 4 Sides on a Square. If each side is 2.5 yd, the Perimeter of the Square would be (4 X 2.5) or 10 yd
A square's area is side^2. The perimeter is side*4. I'll assume you meant 25 square yards. A=25 yd=s^2 s=5 yd P=5*4 yd=20 yd
16yd
Perimeter = 2*(L+W) = 2*(5+3) = 2*8 = 16 yards.
Perimeter is the length round the outside. A basketball court is a rectangle, so: perimeter = 2 x (length + width) = 2 x (30 yd + 40 yd) = 2 x 70 yd = 140 yd
It's 2 x (9 yd 2 ft) + 2 x (5 yd 2 ft) = 2 x (29 ft) + 2 x (17 ft) = 2 x (46 ft) = 92 ft = 30 yd 2 ft
1 yd = 36 in 6 yd 5 in - 2 yd 7 in = (5 + 1) yd 5 in - 2 yd 7 in = 5 yd (36 + 5) in - 2 yd 7 in = (5-2) yd (36 + 5 - 7) in = 3 yd 34 in.
Given that L x W = 75 yd2 and L = 3W. Substituting 3W for L, 3W x 1W = 3 W2 = 75 yd2 Dividing each side by 3, W2 = 25 yd2 Taking the square root of each side, W = 5 yd so L = 3 x 5 yd = 15 yd Perimeter = 2 x (L + W) = 2 x (15 yd + 5 yd) = 2 x 20 yd = 40 yd
well the formula is p=2(l+w) p stands for perimeter l stands for length w stands for width P= l+l+w+w =5+5+3+3 = 16
Assuming that you have a rectangle shaped area, 20 yards long by 15 yards wide, and you want to completely enclose the area with the fencing, then you have a problem where you need to find the perimeter of a rectangle. Perimeter = 2 * Length + 2 * Width Perimeter = 2 * (20 yd) + 2 * (15 yd) = 40 yd + 30 yd = 70 yards
Perimeter = 2*(L+W) = 2*(3+7) = 2*10 = 20 yards. By the way, conventionally, the length is the bigger dimension.
49
7 yd 1 ft - 5 yd 2 ft = 22 ft - 17 ft = 5 ft = 1 yd 2 ft.