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Q: What is the perimeter of a rhombus with sides 2.4 centimeters long?

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8 X 4 = 32 Answer: 32 inches

it would be 21/3

The perimeter of any pentagon is the sum of its 5 sides. So if a regular pentagon has sides that are 4 long, its perimeter is 20.

16 cm

Since a pentagon has 5 sides, you divide the perimeter by 5.

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That rhombus has a perimeter of 18.88 feet.

52 cm

We need to know the lengths of the other sides to help you with this.

8 X 4 = 32 Answer: 32 inches

If each side is 1cm long then its perimeter is 8 times 1cm = 8 centimeters

it would be 21/3

Well, that is extremely simple- 36 inches. A rhombus is a quadrilateral so it has four sides and if each one is 9 inches long it's 36. 9x4=36

If an equilateral triangle is 3 centimeters long then the perimeter of the triangle is 9 centimeters. The perimeter is found by adding up the lengths of all the sides of an object.

Perimeter = sum of three sides = 96 cm One side of 34cm, another of 25 cm so the third is 96 - 34 -25 = 37 cm

24cm (4 sides x 6 = 24)

A regular pentagon has five sides of the same length. Therefore, the perimeter of the shape will be 8 x 5 = 40 centimetres.

The perimeter of this square measures 4 x 1 = 4 decimeters. As 1 decimeter = 10 centimeters then 4 decimeters = 4 x 10 = 40 centimeters.

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