8 X 4 = 32 Answer: 32 inches
it would be 21/3
The perimeter of any pentagon is the sum of its 5 sides. So if a regular pentagon has sides that are 4 long, its perimeter is 20.
If it is an equilateral triangle with 3 equal sides of 4m then its perimeter is 12cm
16 cm
That rhombus has a perimeter of 18.88 feet.
52 cm
We need to know the lengths of the other sides to help you with this.
8 X 4 = 32 Answer: 32 inches
If each side is 1cm long then its perimeter is 8 times 1cm = 8 centimeters
Well, that is extremely simple- 36 inches. A rhombus is a quadrilateral so it has four sides and if each one is 9 inches long it's 36. 9x4=36
If an equilateral triangle is 3 centimeters long then the perimeter of the triangle is 9 centimeters. The perimeter is found by adding up the lengths of all the sides of an object.
Perimeter = sum of three sides = 96 cm One side of 34cm, another of 25 cm so the third is 96 - 34 -25 = 37 cm
it would be 21/3
24cm (4 sides x 6 = 24)
A regular pentagon has five sides of the same length. Therefore, the perimeter of the shape will be 8 x 5 = 40 centimetres.
The perimeter of this square measures 4 x 1 = 4 decimeters. As 1 decimeter = 10 centimeters then 4 decimeters = 4 x 10 = 40 centimeters.