It,s easy. a+b+c= perimeter
perimeter of rectangle=2(l+b) l=length of the rectangle b=breadth of the rectangle
Given any number b > 2, let l = 2b/(b-2) then the rectangle with sides of l and b will have an area = l*b = 2b/(b-2) * b = 2b2/(b-2) and perimeter = 2*(l+b) = 2*[2b/(b-2) + b] =2*[2b/(b-2) + b(b-2)/(b-2)] = 2/(b-2)* [2b+b2-2b] = 2b2/(b-2) So that the area and perimeter have the same numeric value.
If the shape is in the form of a wide letter L, then the perimeter is the same as the height of the letter L x the width of the base of the letter L.
you add the sides together . a /\b a+b+c /_\ c
It,s easy. a+b+c= perimeter
Perimeter of a parallelogram = 2 (A + B) 'A' and 'B' are the lengths of any two adjacent (touching) sides.
you add up the measures of the sides Perimeter=a+b+c
the perimeter of a rectangle is calculated by : 2*(l+b)
we have the formula to find perimeter of the rectangle i.e. perimeter = 2(l+b) where l = length b = breadth substitute l=96 and perimeter = 334,we get 334 = 2(96+b) 334/2=96+b, 167 = 96 + b b = 167-96 =71. b = breadth of the given rectangle is 71.
perimeter of rectangle=2(l+b) l=length of the rectangle b=breadth of the rectangle
The perimeter of a trapezium is the summation of all its sides. So, if a, b, c and d were the sides of the trapezium, then the perimeter would be a plus b plus c plus d.
Area:A=1/2bhA=Area b=Base h=HeightPerimeter:P=a+b+cP=Perimeter a,b,c=side lengths of the triangle
a + b + c
a+b+c
IF triangles 'A' and 'B' are similar (they both have the same angles),then the perimeter of 'B' is 8 times the perimeter of 'A'.If they're not similar, then the ratio of areas doesn't tell you the ratioof perimeters.
B+h*2 =9*-=423