Coodinate: (2, 5)
Equation: y = 7x+13
Slope: 7
Perpendicular slope: -1/7
Perpendicular equation: 7y = -x+37
Both equations intersect at: (-1.08, 5.44)
Perpendicular distance: square root of [(-1.08-2)^2+(5.44-5)^2] = 3.111 to 3 d.p.
The same rules apply but it might help if you turn the fraction into a decimal.
300m is a measure of distance. A decimal is a way of representing numbers and the two have little to do with one another.
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
decimal
It is a number with a decimal point. It is not necessarily a decimal number because 24 (no decimal pont) is a decimal number.It is a number with a decimal point. It is not necessarily a decimal number because 24 (no decimal pont) is a decimal number.It is a number with a decimal point. It is not necessarily a decimal number because 24 (no decimal pont) is a decimal number.It is a number with a decimal point. It is not necessarily a decimal number because 24 (no decimal pont) is a decimal number.
Equation: 5x-2y = 3 Perpendicular equation: 2x+5y = -14 Both equations intersect at: (-13/29, -76/29) Perpendicular distance to 3 decimal places: 3.714
Equation: y = 2x+10 and slope is 2 Perpendicular slope: -1/2 Perpendicular equation: 2y = -x+20 Both equations intersect at: (0, 10) from (4, 8) Distance: square root of (0-4)^2 plus (10-8)^2 = 4.472 to three decimal places
Points: (0, 5) and (3, 0) Midpoint: (1.5, 2.5) Slope: -5/3 Perpendicular slope: 3/5 Perpendicular equation: y--5 = 3/5(x--3) => 5y = 3x-16 Distance is the square root of (1.5--3)^2+(2.5--5)^2 = 8.746 to three decimal places
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
Points: (4, -6) and (2, -3) Slope: -3/2 Equation: 2y = -3x Perpendicular slope: 2/3 Perpendicular equation: 3y = 2x+3 Both equations meet at: (-6/13, 9/13) Distance from (6, 5) to (-6/13, 9/13) is 7.766 units rounded to 3 decimal places
If you mean points of (5, 7) and (-3, 4) then the distance is the square root of 73 or about 8.544 rounded to three decimal places
Points: (-3, -4) and (-8, 1) Distance: square root of 50 or about 7.071 to three decimal places
If you mean (-2, -1) and (5, 3) then it is the square root of 65 which is about 8.062 to three decimal places
If you mean points of (-5, 1) and (-2, 3) then using the distance formula it is the square root of 13 or about 3.61 rounded to 2 decimal places