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What is the perpendicular distance from the coordinate of 2 5 that meets the staight line of y equals 7x plus 13 at right angles on the Cartesian plane showing all work and answer to 3 decimal places?
Wiki User
∙ 9y ago
Coodinate: (2, 5)
Equation: y = 7x+13
Slope: 7
Perpendicular slope: -1/7
Perpendicular equation: 7y = -x+37
Both equations intersect at: (-1.08, 5.44)
Perpendicular distance: square root of [(-1.08-2)^2+(5.44-5)^2] = 3.111 to 3 d.p.
Wiki User
∙ 9y ago
Wiki User
∙ 9y agoy = 7x + 13Gradient = 7 => gradient of perpendicular = -1/7
=> eqn of line through (2, 5), with a gradient of -1/7 is
(y - 5) = -1/7*(x - 2)
=> 7y - 35 = 2 - x
=> x + 7y - 37 = 0
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