pH + pOH = 14 12.4 + pOH = 14 pOH = 1.6 pOH = -log[OH-] 1.6 = -log[OH-] 10-1.6 = [OH-] = 0.0251 M
pH + pOH = 14. So pOH = 14 - 5.33 = 8.67 pOH = -log[OH-] [OH-] = 2.14 x 10-9 M
pH + pOH = 14. So pOH = 14 - 10.95 = 3.05 pOH = -log[OH-] [OH-] = 8.91 x 10-4 M
[OH-] = 3.31 log[OH-] = pOH = .51982 14-pOH = pH = 13.48
pH and pOH are a measure of the concentration of the hydronium ions and hydroxyl ions respectively in the solution. pH = -log[H+] pOH = -log[OH-] and they are related: pH + pOH = 14
pOH= -log[OH]
pOH = -log [OH-} pOH = -log 9.0x10^-7 pOH = 8.15
pOH= -log(0.0220M OH) pH=14-pOH pH=12.34242268
1.70
poh=14-ph
pH + pOH = 14. So pOH = 14 - 6 = 8 pOH = -log[OH-] [OH-] = 10-8 M
pH + pOH = 14. So pOH = 14 - 10 = 4 pOH = -log[OH-] [OH-] = 10-4 M