Prime factorization of 7 = 7 Prime factorization of 56 = 2*2*2*7 Common number(factor in factorization) or simply H.C.F.= 7 L.C.M. = H.C.F. * Product of other numbers = 7*2*2*2 = 56 In this case 7 is an exact divisor of 56, therefore L.C.M. = 56
Prime Factorization of 24 and 56Prime factorization of 24 is:2 X 122 X 2 X 62 X 2 X 2 X 3The prime factorization of 56 is:2 X 282 X 2 X 142 X 2 X 2 X 7
You cannot use exponents for this problem. 7x4x2yes you can it is 7x23
The base of an exponent is the main number. For example in 56 the number 5 is the base and 6 is the exponent.
Prime factors of 56 First, what two numbers multiplied give you 56? 7 x 8 Is either of these a prime number?? Yes, 7 is prime. What about 8? What two numbers multiplied together give you 8? 2 x 4 Is either of these a prime number?? Yes, 2 is prime. What about 4? What two numbers multiplied together give you 4? 2 x 2 Is either of these a prime number?? Yes, both are prime. Combining our individual results, the prime factorisation of 56 is 7 x 2 x 2 x 2
56 = 23 x 71
23 x 7 = 56
The prime factorization of 56 is:7 x 23 = 56
56 is 8*7
The prime factorization of 18 is 2 x 3 x 3. The prime factorization of 56 is 2 x 2 x 2 x7.
56 prime factorization 2*2*2*7 exponents: 23*7 * = multiply
56
56 and 44
The prime factorization of 21 is 3 x 7 = 21The prime factorization of 56 is 2 x 2 x 2 x 7 = 56The GCF of 21 and 56 is 7.
Yes: 56 = 23 × 7
2*2*2*7 = 56
the prime factorization of 56 is a prime number that are only divisible by twounique factors.