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1300 = 2 * 2 * 5 * 5 * 13 = 22 * 52 * 13

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Q: What is the prime factorization of 1300 using exponents?
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Related questions

What is the prime factorization of the number 1300 with exponents repeated factors appear?

22 x 52 x 13 = 1300


What is the prime factorization for the number 1300 using exponets?

The prime factorization of 1300 is 2^2 * 5^2 * 13.


Find the prime factorization of 1300 use exponents when repeated factors appear?

22 x 52 x 13


What is Prime factorization of 1300?

As a product of its prime factors: 2*2*5*5*13 = 1300


What is the prime factor of 1300 with exponents when repeated factors appear?

2^2 x 5^2 x 13


What is the prime factorization of 1300?

2 x 2 x 5 x 5 x 13 = 1300


What are the factors and prime factors of 1300?

The factors of 1300 are the numbers that can be multiplied together to equal 1300. These include 1, 2, 4, 5, 10, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, and 650. The prime factors of 1300 are the prime numbers that can be multiplied together to equal 1300, which are 2, 5, and 13. Therefore, the prime factorization of 1300 is 2^2 * 5^2 * 13.


What is the prime factorization of 1300 in exponent form?

1 + 2 + 4 + 5 + 10 + 13 + 20 + 25 + 26 + 50 + 52 + 65 + 100 + 130 + 260 + 325 + 650 + 1300 = 3,038


Are 145 and 1300 relatively prime?

No, they are not relatively prime.No.


Is 1300 prime?

1300 is not a prime number. Its positive integer factors are: 1, 2, 4, 5, 10, 13, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, 650, 1300


What is the factorization of 1300?

1300 = 2 x 2 x 5 x 5 x 13 = 2^2 x 5^2 x 13


Who was the prime minister of Romania in 1300-1600?

In this period any Romanian principality hadn't a prime minister !