What is the prime factorization of 252 in exponential form?

Answer 1

The prime factorization of 252 is 2^2 * 3^2 * 7. This means that 252 can be expressed as the product of these prime factors raised to their respective powers. In exponential form, this would be written as 2^2 * 3^2 * 7.

Answer 2

252 is a composite number because it has factors other than 1 and itself. It is not a Prime number.

The 18 factors of 252 are 1, 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, 126, and 252.

The factor pairs of 252 are 1 x 252, 2 x 126, 3 x 84, 4 x 63, 6 x 42, 7 x 36, 9 x 28, 12 x 21, and 14 x 18.

The proper factors of 252 are 1, 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, and 126 or,
if the definition you are using excludes 1, they are 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, and 126.

The prime factors of 252 are 2, 2, 3, 3, and 7. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.

The distinct prime factors of 252 are 2, 3, and 7.

The prime factorization of 252 are 2 x 2 x 3 x 3 x 7 or, in exponential form, 22 x 32 x 7.