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1/4 = 0.25

If the second die is 1 or 2, then there are 12 possible outcomes.

To score 7: 5+2 or 6+1 ⇒ 2 rolls

To score 8: 6+2 ⇒ 1 roll

⇒ to score 7 or 8: 2 + 1 = 3 rolls

So there are 3 rolls to score the required sums out of 12 possible rolls, giving a probability of:

3/12 = 1/4 = 0.25

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Q: What is the probability if rolling a sum of 7 or 8 given the second die is a 1 or a 2?
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