The following is the probability of obtaining 4 ones IN THE FIRST FOUR rolls of a fair die.
Pr(4 1's) = Pr(1)*Pr(1)*Pr(1)*Pr(1) since the events are independent.
Pr(4 1's) = Pr(1)4 = (1/6)4 = 1/1296 = 0.000772
the probability of tossing a coin and it landing on head is a 1 in 2 chance the probability of rolling a 5 on a dice is a 1 in 6 chance
The answer depends on what numbers are on the faces of the dice.
The probability of rolling doubles on a fair six-sided die is 1/6. To roll doubles 7 times in a row, you would need to multiply this probability by itself 7 times, resulting in (1/6)^7. This equals approximately 1 in 78,364,164,096, which means the chances of rolling doubles 7 times in a row are extremely low.
The probability of rolling a six with a standard die five times in a row is (1 in 6)5 which equals 1 in 7776 or about 0.0001286.
It is 6/36 = 1/6.
The probability of rolling an 8 is Zero.
The probability is 0.
The probability is 1.
Assume the given event depicts flipping a fair coin and rolling a fair die. The probability of obtaining a tail is ½, and the probability of obtaining a 3 in a die is 1/6. Then, the probability of encountering these events is (½)(1/6) = 1/12.
Assuming that it is a 6-sided die, the answer is 1/3.
1/6 or 1 in 6 :)
Assuming the numbers are 1-6, the probability is 0.
One in six.
It is 1/6.
It is 0.1962
If you roll the die often enough, the probability of getting a 2 ones in a row is 1. In only 2 rolls, the answer is (1/6)*(1/6) = 1/36
5/36 in a single roll.